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year1 sem1
BMS1011
week 6 - enzymes
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Henry DAI
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Enzymes
theyre biological
catalysts
they increase the rate of biological
reactions
MOST enzymes are
proteins
enzymes are
SPECIFIC
for their given reaction.
why do we need enzymes
enzymes increase the rate of biochemical reactions (
catalyse
)
many enzymes are part of
coordinated
pathways, catalysing stepwise reactions
they are very
specific
for their substrate
cool fact
many diseases are due to enzymes not functioning properly
many drugs target enzymes
enzymes more facts
they
are
NOT
used up during the process
enzymes are mostly
GLOBULAR
proteins
the
native
structure is critical for the activity of enzyme
enzyme examples
DNA polymerase: enzyme related to DNA replication
Hexokinase: in glycolysis, involving phosphorylation of glucose to glucose 6-phosphate
Pyruvate dehyrogenase (PDH): pyruvate --> acetal-CoA important metabolism reaction
A)
DNA polymerase
B)
hexokinase
C)
pyruvate
3
active site
the region in the enzyme responsible for
catalysing
whatever reaction
it is where the substrate binds to, for
catalysis
the process
enzyme + substrate =
enzyme-substrate complex
(ES)
it becomes the
enzyme-product
(
EP
)
complex
then it's
Enzyme
+
product
(
E+P
) because enzyme is
unchanged
reaction
coordinate
graphs
reaction coordinate graph
A)
activation energy
1
how to speed up reaction
increase temperature
lower
the activation energy (enzymes)
change
the pathway of reaction (enzymes)
uncatalysed vs enzyme-catalysed reaction
A)
lower
B)
reaction coordinate
C)
free
3
example
without enzymes, bending a metal stick requires lots of energy
at the point right before it bends, it can return back to straight or be bent
this is called transition state (green)
A)
transition state
1
disadvantage of lock and key model
the enzyme
SLOWS
the
rate
of
reaction
(bc it's
locked
)
since it requires more
free energy
(
G
) to reach
transition state
, than
uncatalysed
induced fit model
shows how the enzyme's
active site
adjusts to that of the substrate
results in
lower activation energy
induced fit model steps
enzyme binds to substrate
weakly
but enough to be
specific
(forms
ES
complex)
enzyme undergoes
conformational
change to bind tighter to the
transition
state (
lower
activation energy)
ES complex is converted to
enzyme-product
Enzyme
releases
the
product
common amino acids as enzymes
tend to have side
acidic
and
basic
forms of side chains
Eg.
Histidine's
side chain has a pKa of around
7
, meaning it can easily exist as both
protonated
and
deprotonated
form
terms
cofactor: one or more
INORGANIC
ions involved in the active site reaction (eg.
Fe2
+,
Mg2
+,
Zn3
+)
coenzyme: a larger ORGANIC molecule that carries
electrons
or
functional
groups required for catalysis, mostly vitamins.
prosthetic group: a coenzyme or metal ion covalently tightly bound to the enzyme. (eg. heme in hemoglobin)
quantifying enzyme kinetics
dependent on how much product is made (DV)
in the graph, it plateaus because the substrate eventually runs out
the dotted lines = initial velocity (V0), shows rate
A)
product
B)
time
C)
initial velocity
3
graphing initial velocity against substrate concentration
as [S] increases, V0 reaches an
asymptote
at Vmax (initial velocity is
maxed
)
Km is the [S] that is
half
of Vmax
this graph is used to determine an enzyme's
optimal
perfomance
graphing initial velocity against substrate concentration
as [S] increases, V0 reaches an asymptote at Vmax (initial velocity is maxed)
Km is the [S] that is half of Vmax
this graph is used to determine an enzyme's optimal perfomance
A)
Km
B)
substrate
C)
initial velocity
D)
Vmax
4
Michaelis constant (Km)
the substrate concentration at which
V
0
is
one-half
V
max.
it is for a GIVEN enzyme concentration
Km is proportional to enzyme concentration
Km NEVER changes
lineweaver-Burk plot - 1/V0 AGAINST 1/[S]
this is MORE USEFUL
gives a straight line
1/y-int = Vmax
-1/x-int = Km
Km/Vmax = slope
A)
slope
1
Kcat constant
the
maximal
rate for an enzyme at saturation with substrate
it represents the
NUMBER
of substrate molecules
CONVERTED
into product in a given unit of time.
aka. enzyme's
turnover
rate.
It has units of "per time".
enzyme's are saturated when..
they are working at their
maximum
due to the
maximum
amount of substrate
do these values change or not
V0: changes with [S], but
plateaus
near Vmax
Vmax:
proportional
to [E]
Km:
constant
Kcat:
constant
(?)
question
Vmax=260 and Km=1 AT[E]=100nM
Vmax=? and Km=? AT [E]=200nm
A)
520
B)
1
2
Km trends
the
lower
the Km, the more efficient
lower Km = enzyme requires
less
substrate to achieve half Vmax
enzyme INHIBITION
the action of enzymes can be inhibited (reduced)
types:
IRREVERSIBLE
and
REVERSIBLE
types: competitive vs uncompetitive
inhibition types
irreversible
: when a molecule permanently bonds to an enzyme, forming
covalent
bond. resulting in non-reactive enzyme
reversible
: when a molecule binds and unbinds from enzyme. Enzyme action comes back after
inhibitor
is removed.
competitive inhibition
comp: the inhibitor
COMPETES
with the substrate for binding to enzyme
diagram: 2 possible pathways
A)
competitive
B)
active site
2
uncompetitive inhibition:
inhibitor binds to a
SEPARATE
site on the ES complex
the conformational change (E+S) allows inhibitor to bind
CANNOT be prevented by increasing substrate concentration (competitive can)
A)
uncompetitive
1
mixed inhibition
The inhibitor binds to separate site on either the ENZYME or ES COMPLEX
2 ways of getting to ESI (1 step and 2 step)
A)
ESI
1
enzyme inhibitor examples (pharmacy)
aspirin
: IRREVERSIBLE inhibition of COX
statins
: REVERSIBLE, competitive inhibition of HMG-CoA reductase
competitive inhibition -
lineweaver-burk
Km
increases
as [
Inhibitor
] increases
same y-int =
Vmax
doesn't change
Uncompetitive inhibition - lineweaver-burk
y-int and x-int
increase
as [Inhibitor] increases
this means that Vmax is
decreases
as [Inhibitor] increases
inhibitor binds to ES and removes
space
for substrate to bind to enzyme, thus
lower
Vmax
Mixed inhibition - linewaeaver-burk
Vmax
decreases
as [Inhibitor]
increases
(y-int
increases
)
Km
increases
as [Inhibitor] increases (
x-int
increases)
regulatory enzymes
to control the rate of
metabolic
pathways or
reactions
eg. if need more or less of a product, these enzymes
regulates
this rate
regulatory enzymes --> allosteric enzymes
type or regulatory enzyme
are quaternary structures (aka. multi-domain)
involves reversible and non-covalent binding of allosteric modulators/effectors onto a SEPARATE SITE of the enzyme (not active site)
when binded, conformational change occurs which affects substrate binding (bad and good)
A)
allosteric
1
positive allosteric enzyme example
C=
catalytic
domain
R=
regulatory
domain
1)substrate can't fit initially
2)
positive
allosteric modulator binds to regulatory domain
3) conformational change occurs
ALLOWING
substrate to bind
allosteric enzyme KINETICS
if
positive
modulator is involved
low
activity T-state: enzyme when it has not binded to substrate
high
activity R-state: enzyme when there is lots of substrate (undergoes positive conformational change to accept substrate better)
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