Newton's law of restitution states that e, the coefficient of restitution, is equal to the speed of separationdivided by the speed of approach, or v/u.
e can only have a value between 0 and 1, where e = 0 is a completely inelastic collision and particles coalesce (stick together) on impact, and e = 1 is a perfectly elastic collision.
To find the speed with which a particle rebounds from a fixed plane, multiply the approach speed by e.
The conservation of linear momentum can be written as m1u1+m2u2 = m1v1+m2v2.
The loss of kinetic energy is the kinetic energy beforeminus the kinetic energy after.
When a smooth particle hits a smooth surface, the impulse acts perpendicular to the surface, through the centre of the sphere.
When a smooth particle hits a smooth surface, the component of velocity parallel to the surface is unchanged.
When a smooth particle hits a smooth surface, the component of velocity perpendicular to the surface is divided by e.
When two particles collide, the impulse acts along the line of centres.
When two particles collide, the components of velocities perpendicular to the line of centres are unchanged, but newtons law of restitution applies to the parallel components.
The components of a vector a in the direction of another vector b is given by (a . b/ |b^2| ) [b], where [b] is a vector.
Where the wall is not a long an i or j axis, the scalar product of the wall and the vector of either the initial or final speed will be equal.
Where the line of centres is not along the i or j axis, newtons law of restitution is adapted to become -eu . I = v . I, where u, v and I are vectors and . represents the scalar product.