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1. PRINCIPLES OF CHEMISTRY
Chemical formulae equations and calculations
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Cards (30)
Word equation
A chemical
reaction
written using the
names
of the reactants and products
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Balanced chemical equation
A chemical equation where the number of
atoms
of each element is the
same
on both sides of the equation
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State symbols
(g) means
gas
(s) means
solid
(l) means
liquid
(aq) means
aqueous
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Word equation
hydrochloric acid +
sodium
hydroxide ->
sodium
chloride + water
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Balanced chemical equation
HCl + NaOH ->
NaCl
+
H2O
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Balancing an equation
1. Make sure there are the
same
number of each
element
on each side of the equation
2. Use big numbers at the front of a compound to
balance
it e.g. 3H2O
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Relative
formula mass (
Mr
)
Sum of the
relative atomic
masses of the atoms in the
numbers
shown in the formula
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In a balanced chemical equation, the sum of
Mr
of reactants in quantities shown = sum of
Mr
of products in quantities shown
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Mole
(
mol
)
The unit for the
amount
of a substance
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The
mass
of one
mole
of a substance in grams is numerically equal to its relative formula mass
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One
mole
of a substance contains the same number of the stated particles, atoms, molecules or ions as
one
mole of any other substance
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Converting between moles and grams
1.
Moles
= Mass / Relative atomic mass
2. Mass =
Moles
x Relative atomic mass
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Calculating moles
Moles =
42g
/
12
= 3.5 moles
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Interpreting chemical equations in terms of moles
1. Find
moles
of one substance
2. Use
balancing numbers
to find moles of desired reactant or product
3. Mass =
Moles
x
Molar mass
(of the product)
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Percentage yield
Amount of product produced /
Maximum amount of product possible
x
100
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Reasons percentage yield is less than 100%
Reaction may not go to
completion
because it is
reversible
Some of the product may be
lost
when it is separated from the
reaction mixture
Some of the reactants may react in ways
different
to the
expected reaction
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Determining formula of a compound experimentally
1. Weigh some
pure magnesium
2.
Heat magnesium
to burning in a crucible to form
magnesium oxide
3. Weigh the
mass
of the
magnesium oxide
4. Calculate the ratio of moles of
magnesium
to moles of
oxygen
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Reasons why a reaction may not go to completion
1. Reaction may not go to completion because it is
reversible
2. Some of the product may be
lost
when it is
separated
from the reaction mixture
3. Some of the reactants may react in ways
different
to the
expected
reaction
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Yield
The
amount
of
product
obtained
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Experiment to find formula of magnesium oxide
1. Weigh some
pure
magnesium
2. Heat magnesium to
burning
in a crucible to form
magnesium oxide
3. Weigh the
mass
of the
magnesium oxide
4. Calculate ratio of moles of
magnesium
to moles of
oxygen
5. Use ratio to form
empirical
formula
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Empirical formula
The simplest whole number
ratio
of atoms of each
element
in a compound
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Molecular formula
The number of
atoms
of each
element
in a compound
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Calculating empirical formula from molecular formula
1. If there is a common multiple, the empirical formula is the simplest whole number
ratio
2. If there is no common multiple, the empirical formula is the same as the
molecular
formula
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Calculating molecular formula from empirical formula and relative molecular mass
1. Find
relative molecular mass
of the empirical
formula
2. Divide relative
molecular mass
of compound by that of the
empirical formula
3. Multiply the number of each type of
atom
in the
empirical
formula by this number
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Concentration of a solution
Can be measured in
mass
per given volume of solution e.g.
grams
per dm3 (g/dm3)
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Calculating
concentration
of a solution
Concentration
(g dm-3) =
mass
of solute (g) / volume (dm3)
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Calculating mass of solute in a given volume of a known concentration
Mass =
concentration
x
volume
i.e. g = g/dm3 x dm3 (think about the units!)
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Molar volume of a gas
Equal amounts in mol. of gases occupy the
same
volume under the
same
conditions of temperature and pressure (e.g. RTP)
Volume of 1 mol. of any gas at RTP (room temperature and pressure:
20
degrees C and 1 atmosphere pressure) is
24
dm3
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Calculating volume of gas at RTP
Volume (dm3) of gas at RTP =
Mol. x 24
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Know how to determine the formula of a metal
oxide
by
combustion
(e.g. magnesium oxide) or by reduction (e.g. copper(II) oxide)
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