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Cards (9)
[Cu(H2O)6]2+ (
Pale blue
,
octahedral
)
+
NH3
= [Cu(NH3)4(H2O)2]2+ (
Royal blue
,
octahedral
)
+
HCl
= [CuCl4]2- (
Yellow-green
,
tetrahedral
)
[Co(H2O)6]2+ (
Pink
,
octahedral
)
+
HCl
= [CoCl4]2- (Blue, tetrahedral)
Cr3+
is amphoteric
(
small
amount NaOH) Cr3+ +
3OH-
=
Cr(OH)3
(
Grey-green
precipitate)
(
Excess
NaOH) Cr(
OH
)3 + 3OH- =
[Cr(OH)6]3-
(
Green
solution)
Fe2+
,
Fe3
+ and
Cu2+
are not amphoteric.
Fe2+
+
2OH-
=
Fe(OH)2
(
Dark green
precipitate)
Fe3+
+
3OH-
=
Fe(OH)3
(
Red-brown
precipiate)
Cu2+ + 2OH- = Cu(OH)2 (Pale blue precipitate)
2Cu2+
+
4I-
=
2CuI
(
white
solid) +
I2
(
Brown
solution)