A reducing agent donates electrons - looses electrons itself
The reducing power of the halides increases down group 7 because as the ions get bigger it is easier for the outer electrons to be given away as the attraction from the nucleus on them becomes weaker
NaF and NaCl :
F- and Cl- ions are not strong enough reducing agents to reduce the S in H2SO4 . No redox reactions occur only acid-base reactions occur
oxidation states of halide and sulfur stay the same (-1 and +6)
Reactions of NaF and NaCl with H2SO4:
NaF(s) + H2SO4 (l) ----> NaHSO4 (s) + HF(g)
NaCl(s) + H2SO4 (l) ----> NaHSO4 (s) + HCl(g)
OBSERVATIONS:
White misty fumes of HF and HCl are evolved
NaBr:
Br- ions are stronger reducing agents than Cl- and F- and after the initial acid-base reaction, the bromide ions reduce the sulfur in H2SO4 from +6 to + 4 in SO2