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Chemistry
Paper One
Quantitative chemistry
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Created by
Alicja Mazurkiewicz
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Cards (39)
Law of
conservation
of
mass
No atoms are lost or made during a chemical reaction so the
mass
of the products =
mass
of the reactants
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Balanced chemical equation
The numbers of
atoms
of each element involved are the
same
on both sides of the equation
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Relative formula mass
(
Mr
)
Sum of the
relative atomic
masses of the atoms in the
numbers
shown in the formula
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In a balanced chemical equation, the sum of
Mr
of reactants in quantities shown = sum of
Mr
of products in quantities shown
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If a reaction appears to involve a
change
in
mass
Check if this is due to a reactant or a product as a
gas
and its
mass
has not been taken into account
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When a metal reacts with
oxygen
, the
mass
of the metal oxide product is greater than the mass of the metal
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Whenever a measurement is made there is always some
uncertainty
about the result obtained
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Estimations of uncertainty
Be prepared to make estimations of uncertainty when making chemical measurements
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Mole
The unit used to measure
chemical
amounts
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The
mass
of one
mole
of a substance in grams is numerically equal to its relative formula mass
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One
mole
of a substance contains the same number of the stated particles, atoms, molecules or ions as
one
mole of any other substance
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Converting between moles and grams
Use the triangle or the equation:
mass
= moles x
molar mass
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The number of atoms, molecules or ions in a
mole
of a given substance is the
Avogadro
constant: 6.02 x 10^23 per mole
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Balanced symbol equation
Can be interpreted in terms of
moles
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The total
moles
of one element must be the
same
on both sides of the equation
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Balancing numbers in a symbol equation
Convert the masses in
grams
to amounts in
moles
b. Convert the numbers of
moles
to
simple whole number ratios
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Limiting reactant
The reactant that is used up / not in excess (since it
limits
the amount of
products
)
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If a
limiting
reactant is used, the amount of product produced is restricted to the amount of the excess reactant that reacts with the
limiting
one
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Concentration of a solution
Measured in
mass
per given
volume
of solution e.g. grams per dm^3 (g/dm^3)
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Calculating mass of solute in a given volume of a known
concentration
Use
mass
= conc x
vol
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A
smaller
volume or
larger
mass of solute
Gives a
higher
concentration
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Percentage yield
Amount of product produced /
Maximum amount of product possible
x
100
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A larger
volume
or smaller
mass
of solute
Gives a
lower
concentration
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Reasons why calculated amount of product may not be obtained
Reaction may not go to
completion
because it is
reversible
Some of the product may be lost when it is
separated
from the
reaction mixture
Some of the
reactants
may react in ways different to the
expected reaction
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Yield
Amount of product obtained
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Calculating theoretical mass of a product
1. Calculate mol. of reactant by using
mol. = mass
/
molar mass
2. Use
balancing
numbers to find
mol. of product
3. Calculate
theoretical mass
of a product by using mass = mol. x
molar mass
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Atom economy
A measure of the amount of
starting materials
that end up as
useful products
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Atom economy is important for
sustainable
development and for economic reasons to use reactions with
high
atom economy
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Possible reasons why a particular reaction pathway is chosen/not chosen
Atom economy
Yield
Rate
Equilibrium position
Usefulness
of
by-products
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Concentration of a solution
Measured in
mol. per given volume
of solution e.g. mol. per dm3 (mol./dm3)
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Calculating concentration of a solution
1.
Mass of solute
2.
Volume of solution
3. Moles =
concentration
x
volume
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Calculating
concentration
of unknown solution
1. Work out
moles
of known solution
2. Use
mole
ratio from equation
3. Calculate unknown concentration =
moles
/
volume
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Mass of a solute and the volume of a solution are related to the concentration of the solution through the equation
moles
=
concentration
x volume
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Use mass to find moles: mol. = mass / molar mass, then use
conc.
=
mol.
/ vol.
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If the volumes of two solutions that react completely are known and the
concentration
of one solution is known, the
concentration
of the other solution can be calculated
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To go from cm3 to dm3, divide by 1000
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Equal amounts [in mol.] of gases occupy the same volume under the same conditions of temperature and pressure
The volume of 1 mol. of any gas at room temperature [20 degrees Celcius] and pressure [ 1 atmospheric pressure] is 24 dm3
Volume of gas [dm3] at RTP = Moles x 24