Quantitative chemistry

Cards (39)

  • Law of conservation of mass
    No atoms are lost or made during a chemical reaction so the mass of the products = mass of the reactants
  • Balanced chemical equation
    • The numbers of atoms of each element involved are the same on both sides of the equation
  • Relative formula mass (Mr)

    Sum of the relative atomic masses of the atoms in the numbers shown in the formula
  • In a balanced chemical equation, the sum of Mr of reactants in quantities shown = sum of Mr of products in quantities shown
  • If a reaction appears to involve a change in mass
    Check if this is due to a reactant or a product as a gas and its mass has not been taken into account
  • When a metal reacts with oxygen, the mass of the metal oxide product is greater than the mass of the metal
  • Whenever a measurement is made there is always some uncertainty about the result obtained
  • Estimations of uncertainty
    Be prepared to make estimations of uncertainty when making chemical measurements
  • Mole
    The unit used to measure chemical amounts
  • The mass of one mole of a substance in grams is numerically equal to its relative formula mass
  • One mole of a substance contains the same number of the stated particles, atoms, molecules or ions as one mole of any other substance
  • Converting between moles and grams
    Use the triangle or the equation: mass = moles x molar mass
  • The number of atoms, molecules or ions in a mole of a given substance is the Avogadro constant: 6.02 x 10^23 per mole
  • Balanced symbol equation
    Can be interpreted in terms of moles
  • The total moles of one element must be the same on both sides of the equation
  • Balancing numbers in a symbol equation
    Convert the masses in grams to amounts in moles
    b. Convert the numbers of moles to simple whole number ratios
  • Limiting reactant
    The reactant that is used up / not in excess (since it limits the amount of products)
  • If a limiting reactant is used, the amount of product produced is restricted to the amount of the excess reactant that reacts with the limiting one
  • Concentration of a solution
    Measured in mass per given volume of solution e.g. grams per dm^3 (g/dm^3)
  • Calculating mass of solute in a given volume of a known concentration
    Use mass = conc x vol
  • A smaller volume or larger mass of solute

    Gives a higher concentration
  • Percentage yield

    Amount of product produced / Maximum amount of product possible x 100
  • A larger volume or smaller mass of solute

    Gives a lower concentration
  • Reasons why calculated amount of product may not be obtained
    • Reaction may not go to completion because it is reversible
    • Some of the product may be lost when it is separated from the reaction mixture
    • Some of the reactants may react in ways different to the expected reaction
  • Yield
    Amount of product obtained
  • Calculating theoretical mass of a product
    1. Calculate mol. of reactant by using mol. = mass / molar mass
    2. Use balancing numbers to find mol. of product
    3. Calculate theoretical mass of a product by using mass = mol. x molar mass
  • Atom economy
    A measure of the amount of starting materials that end up as useful products
  • Atom economy is important for sustainable development and for economic reasons to use reactions with high atom economy
  • Possible reasons why a particular reaction pathway is chosen/not chosen
    • Atom economy
    • Yield
    • Rate
    • Equilibrium position
    • Usefulness of by-products
  • Concentration of a solution
    Measured in mol. per given volume of solution e.g. mol. per dm3 (mol./dm3)
  • Calculating concentration of a solution
    1. Mass of solute
    2. Volume of solution
    3. Moles = concentration x volume
  • Calculating concentration of unknown solution

    1. Work out moles of known solution
    2. Use mole ratio from equation
    3. Calculate unknown concentration = moles / volume
  • Mass of a solute and the volume of a solution are related to the concentration of the solution through the equation moles = concentration x volume
  • Use mass to find moles: mol. = mass / molar mass, then use conc. = mol. / vol.
  • If the volumes of two solutions that react completely are known and the concentration of one solution is known, the concentration of the other solution can be calculated
  • To go from cm3 to dm3, divide by 1000
  • Equal amounts [in mol.] of gases occupy the same volume under the same conditions of temperature and pressure
  • The volume of 1 mol. of any gas at room temperature [20 degrees Celcius] and pressure [ 1 atmospheric pressure] is 24 dm3
  • Volume of gas [dm3] at RTP = Moles x 24