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SCI MOD 1
projectile angle
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Created by
Zhai Jailani
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Cards (21)
Projectile motion is the combination of horizontal motion with constant velocity and vertical motion with constant acceleration
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Projectile motion launched at an angle
Horizontal velocity (VX) is
constant
Vertical velocity (VY)
decreases
as projectile
rises
Vertical velocity is
zero
at maximum height
Vertical velocity
increases
as projectile returns to ground
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Variables involved in projectile motion launched at an angle
Horizontal component
Vertical component
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An object is projected from rest at an
upward
angle Theta
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Initial velocity can be resolved into
horizontal
and
vertical
components
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Horizontal velocity is constant due to gravity
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Time to reach maximum height is same as time to return to launch point
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Initial upward velocity is same as final velocity when returning to original height
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Angle of 45 degrees results in maximum range
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Angle of 75 degrees results in maximum height
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Angles of 30 and 60 degrees have the same range
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Angles of 15 and 75 degrees have the same range
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As angle of launch increases, vertical displacement increases
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At maximum height, vertical velocity is zero
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Time to reach maximum height is half of total time of flight
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Theta
Numerical value in degrees expressing the orientation of a projectile
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Solving for maximum height of projectile
1. Use formula: VI * sin(Theta)^2 / (2 * g)
2. Substitute given values
3. Simplify units
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Solving for horizontal displacement (range) of projectile
1. Use formula: VI * cos(Theta) * t
2. First solve for total time of flight
3. Then calculate horizontal displacement
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Baseball player hits a long home run with ball leaving bat at 25 degrees and 30 m/s
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Maximum height reached by ball is 8.20 meters
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Horizontal displacement (range) of ball is 70.42 meters
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