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Cards (140)
Gradient = change in
y
/change in
x
,
y
1
−
y
2
x
1
−
x
2
\frac{y_1-y_2}{x_1-x_2}
x
1
−
x
2
y
1
−
y
2
Midpoint
=
(
x
1
+
x
2
)
/
2
+
(x₁+x₂)/2 +
(
x
1
+
x
2
)
/2
+
(
y
1
+
y
2
)
/
2
(y₁+y₂)/2
(
y
1
+
y
2
)
/2
Equation
of line =
y
−
y
1
=
y-y₁ =
y
−
y
1
=
m
(
x
−
x
1
)
m(x-x₁)
m
(
x
−
x
1
)
m₁ x m₂ =
-1
A
perpendicular bisector
is a line that passes through the midpoint between two points and is
90
degrees to the original line
The
perpendicular
gradient is the
negative reciprocal
of the parallel gradient
If lines intersect then use
simultaneous equations
to find the
coordinate
of intersection
The
linear
model is
y= ax + b
b
is the
value
of y when x = 0
a is the value as
x is increased by 1 unit
, y changes by
m
units
b
2
−
4
a
c
>
0
b²-4ac > 0
b
2
−
4
a
c
>
0
then the quadratic equation will have
two
distinct solutions
b²-4ac = 0 then the quadratic will have
one
solution (repeated or
equal
root)
b²-4ac < 0 then the quadratic equation will have
no
solutions
The quadratic model if the vertex is known is
a
(
x
−
b
)
2
+
a(x-b)²+
a
(
x
−
b
)
2
+
c
c
c
The quadratic model if the
x-intercepts
are known is
y
=
y =
y
=
a
(
x
−
b
)
(
x
−
c
)
a(x-b)(x-c)
a
(
x
−
b
)
(
x
−
c
)
The quadratic model if the x-intercepts or vertex are unknown is
a
x
2
+
ax^2+
a
x
2
+
b
x
+
bx+
b
x
+
c
c
c
Greatest
height =
vertex
If you divide or multiply by a negative number the
inequality
direction must be
reversed
If an unknown variable is on the denominator in an inequality then
multiply
by the
square
of that number
Remainder
theorem states that when
f(x)
is
divided
by
ax-b
then the remained will be f(b/a)
One polynomial is a factor of another polynomial if when
dividing
the polynomials the remainder is
zero
y =
x^3
y =
x^4
Circle standard form is
(
x
−
a
)
2
+
(x-a)^2 +
(
x
−
a
)
2
+
(
y
−
b
)
2
=
(y-b)^2 =
(
y
−
b
)
2
=
r
2
r^2
r
2
Two circle theorems:
The angle in a
semicircle
is a
right
angle
Line from the centre of the circle to the midpoint of a
chord
meets the
chord
at a right angle
Normals and tangents are
perpendicular
to each other
dy/dx
> 0
so
positive increasing
gradient
dy/dx < 0 negative
decreasing
gradient
dy/dx =
0
when at a
turning
point or at a maximum or minimum point
If the
second
derivative equals
zero
then the point could be a
minimum
,
maximum
or a point of
inflection
If a region is
below
the x-axis the integral will be
negative
If a region is above the
x-axis
the integral will be
positive
Integration
can be used to find
enclosed
regions between either a
line
and
curve
or between two
curves
The trapezium rule is a numerical technique that can
approximate
the value of a definite
integral
More
strips
used in the
trapezium
rule = more accurate answer
0! =
1
(
1
+
x
)
n
(1+x)^n
(
1
+
x
)
n
expansion
is only valid for |x| <
1
If a>1 then
a
^
x
models exponential growth
If 0<a<1 then
a
^x models
exponential decay
l
o
g
n
(
n
a
)
=
logn(n^a) =
l
o
g
n
(
n
a
)
=
a
a
a
n^logn(a) =
a
logn(b^a) =
alogn(b)
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