step 1 - high electron density of the C=C π bond repels electrons in the bromine molecule, polarising the Br-Br bond
step 2 - leads to heterolytic fission of the Br-Br bond, with one bromine atom taking the bonding pair of electrons, creating a positively charged bromine which bonds to one of the carbon atoms
step 3 - a positively charged carbocation intermediate forms. the negatively charged bromide ion then bonds to the other carbon atom
step 4 - the final product 1,3-dibromoethane, has a bromine atom bonded to each of the original alkene carbon atoms