The product of the molar concentrations of its ions in a saturated solution, each raised to the power that is the coefficient of that ion in the balanced chemical equation
The more soluble a substance is, the higher the value of Ksp
Solubility equilibrium
When a slightly soluble ionic compound is added to water, some of it dissolves to form a solution, establishing an equilibrium between the pure solid and a solution of its ions
The equilibrium expression is written without including the solid species
Solving for Ksp
1. Take the molarities of the products and multiply them
2. If there are coefficients in front of any of the products, raise the product to that coefficient power (and multiply the concentration by that coefficient)
Factors affecting Solubility and Ksp
Temperature effect: Endothermic reaction - temperature ↑, solubility ↑, Ksp ↑
Exothermic reaction - temperature ↑, solubility ↓, Ksp ↓
Calculating molar solubility of BaSO4
Given Ksp = 1.07*10-10
Common ion effect
Addition of common ion at constant temperature:
Concentration of products ↑
Reaction shifts backward (toward reactants) to get rid of excess products
Reaction returns to first equilibrium state
Ksp remains constant
Experimental work to determine Ksp of potassium acid tartrate (KHT)
1. Aim: Determine Ksp of KHT and study effect of common ion
2. Procedure: Prepare KCl solutions of different concentrations, add to KHT, filter, titrate filtrate with NaOH, calculate Ksp
Preparation of 0.01 M KCl solution from 0.1 M KCl stock solution
Calculating Ksp of KHT
1. In absence of common ion: Ksp = [HT⁻] [K⁺]
2. In presence of common ion: Ksp = [HT⁻] [K⁺ KHT + K⁺ KCl]