Math 9

• \(\sin 0\) = c/b
• \(\cos 0\) = a/c
• \(\tan 0\) = b/a
• \(\csc 0\) = c/b
• \(\sec 0\) = c/a
• \(\cot 0\) = a/b
• If the reference angle is angle A then the opposite side is side a while the adjacent is side b
• Solving Right Triangles


  It simply means that solving all the missing values of sides and angles using trigonometry
• The following are the three cases in solving right triangle:

  1. Give n the reference angle and a side ( leg or hypotenuse )
  2. Given a leg and the hypotenuse
  3. Given two legs
• • sin = opposite/hypotenuse (opp/hyp)
• • cos = adjacent/hypotenuse (adj/hyp)
• • tan = opposite/adjacent (opp/adj)
• • csc = hypotenuse/opposite (hyp/opp)
• • sec = hypotenuse/adjacent (hyp/adj)
• • cot = adjacent/opposite (adj/opp)
• • sin30° = opp/hyp = 1/2
• • cos30° = adj/hyp = √3/2
• • tan30° = opp/adj = 1/√3
• • sec30° = hyp/adj = 2/√3
• • csc30° = hyp/opp= 2
• • cot30° = adj/opp = √3
• • sin60° = opp/hyp = √3/2
• • cos60° = adj/hyp = 1/2
• • tan60° = opp/adj = √3/1
• • sec60° = hyp/adj = 2
• • csc60° = hyp/opp = 2/√3
• • cot60° = adj/opp = 1/√2
• • sin45° = opp/hyp = 1/√2
• • cos45° = adj/hyp = 1/√2
• • tan45° = opp/adj = 1
• • sec45° = hyp/adj = √2
• • csc45° = hyp/opp = √2
• • cot45° = adj/opp = 1
• tan60° = opp/adj = √3/1 = √3