Wave Optics

Cards (28)

  • Superposition of two sinusoidal waves
    π‘₯1(𝑑) = π‘Ž1 cos(πœ”π‘‘ + πœƒ1)
    π‘₯2(𝑑) = π‘Ž2 cos(πœ”π‘‘ + πœƒ2)
  • The two displacements of disturbances have same frequency but different amplitudes and different initial phases
  • Resultant displacement

    π‘₯(𝑑) = π‘₯1(𝑑) + π‘₯2(𝑑)
    = cos (πœ”π‘‘)(π‘Ž1 cosπœƒ1 + π‘Ž2 cos πœƒ2) - sin (πœ”π‘‘)(π‘Ž1 sinπœƒ1 + π‘Ž2 sin πœƒ2)
    π‘₯(𝑑) = π‘Ž cos(πœ”π‘‘ + πœƒ)
  • Resultant disturbance

    • It is also simple harmonic with different amplitudes and initial phases
  • Calculating resultant amplitude and phase
    π‘Ž cos πœƒ = π‘Ž1 cosπœƒ1 + π‘Ž2 cos πœƒ2
    π‘Ž sin πœƒ = π‘Ž1 sinπœƒ1 + π‘Ž2 sin πœƒ2
  • Conditions for

    • Constructive interference: πœƒ1 - πœƒ2 = 0, 2πœ‹, 4πœ‹, ...
    Destructive interference: πœƒ1 - πœƒ2 = πœ‹, 3πœ‹, 5πœ‹, ...
  • Resultant displacement with n displacements
    π‘₯ = π‘₯1 + π‘₯2 + ... + π‘₯𝑛 = π‘Ž cos(πœ”π‘‘ + πœƒ)
    π‘Ž cos πœƒ = π‘Ž1 cosπœƒ1 + ... + π‘Žπ‘› cos πœƒπ‘›
    π‘Ž sin πœƒ = π‘Ž1 sinπœƒ1 + ... + π‘Žπ‘› sin πœƒπ‘›
  • At a point B where 𝑆2𝐡 - 𝑆1𝐡 = πœ†/2, the disturbance from 𝑆1 will always be out of phase with disturbance from 𝑆2
  • At a point C where 𝑆2𝐢 - 𝑆1𝐢 = πœ†, the phase of vibration are exactly the same as the point A
  • Conditions for intensity maxima and minima
    Maxima: 𝑆2𝑃 - 𝑆1𝑃 = π‘›πœ† (𝑛 = 0,1,2,3,...)
    Minima: 𝑆2𝑃 - 𝑆1𝑃 = (𝑛 + 1/2)πœ† (𝑛 = 0,1,2,3,...)
  • Coherence

    Two sources vibrating at a constant phase difference
  • If the phase difference varies rapidly, no stationary interference pattern would occur
  • Resultant displacement and intensity for coherent sources

    𝑦 = 𝑦1 + 𝑦2 = 2π‘Ž cos(πœ‘/2) cos(πœ”π‘‘ + πœ‘/2)
    𝐼 = 4𝐼0 cos^2(πœ‘/2)
  • Intensity for coherent sources

    • Minima: πœ‘ = Β±πœ‹, Β±3πœ‹, Β±5πœ‹, ...
    Maxima: πœ‘ = 0, Β±2πœ‹, Β±4πœ‹, ...
  • For incoherent sources, 𝐼 = 2οΏ½οΏ½0 (no stationary interference pattern)
  • Young's double slit experiment
    Division of a single wavefront into two, which act as if they emanated from two coherent sources
  • Determining positions of maxima and minima in Young's double slit experiment
    𝑦𝑛 = π‘›πœ†π·/𝑑
    Distance between consecutive fringes: 𝛽 = πœ†π·/𝑑
  • Intensity distribution in Young's double slit experiment

    𝐼 = 𝐾(𝐸1 + 𝐸2)^2 = 2𝐼0(1 + cos 𝛿)
    𝛿 = 2πœ‹(𝑆2𝑃 - 𝑆1𝑃)/πœ†
  • Conditions for maxima and minima in Young's double slit experiment
    • Maxima: 𝑆2𝑃 - 𝑆1𝑃 = π‘›πœ†
    Minima: 𝑆2𝑃 - 𝑆1𝑃 = (𝑛 + 1/2)πœ†
  • For incoherent sources in Young's double slit experiment, 𝐼 = 𝐼1 + 𝐼2 (no interference pattern)
  • Intensity distribution for coherent sources in Young's double slit experiment
    𝐼 = 4𝐼0 cos^2(𝛿/2)
  • Constructive interference occurs at π‘₯ = πœ†/4, 3πœ†/4, 5πœ†/4, ...
    Destructive interference occurs at π‘₯ = 0, πœ†/2, πœ†, 3πœ†/2, ...
  • Reflection of wave at π‘₯ = 0 (by rigid end) results in a phase shift of πœ‹
  • Diffraction

    • Spreading-out of a wave when it passes through a narrow opening
    Closely related to interference
  • Fresnel diffraction: Source and screen at finite distances from the diffracting aperture
    Fraunhofer diffraction: Source and screen at infinite distances from the diffracting aperture
  • Single-slit diffraction pattern

    Treat slit as a continuous distribution of point sources
    Intensity 𝐼 = 𝐼0 (sin οΏ½οΏ½/𝛽)^2, where 𝛽 = πœ‹π‘ sin πœƒ/πœ†
  • Positions of minima in single-slit diffraction: π‘š = Β±1, Β±2, Β±3, ...
  • Positions of maxima in single-slit diffraction: 𝛽 = 0, 1.43πœ‹, 2.46πœ‹, ...