Chemistry Final exam

Cards (275)

  • Valence Bond Theory
    • A covalent bond forms when the orbitals on two atoms overlap
    • The shared region of space between the orbitals is called the orbital overlap
    • As two nuclei approach each other their atomic orbitals overlap
    • A covalent bond results when (1) an orbital on one atom overlaps an orbital on a second atom and (2) the single electrons in each orbital combine to form an electron pair
  • Hybridization
    • The mixing of different types of atomic orbitals to produce a set of equivalent hybrid orbitals
    • Hybrid orbitals do not exist in isolated atoms, they are formed only in covalently bonded atoms
    • Hybrid orbitals have shapes and orientations that are very different from those of the atomic orbitals in isolated atoms
    • The number of hybrid orbitals in a set is equal to the number of atomic orbitals that were combined to produce the set
    • All orbitals in a set of hybrid orbitals are equivalent in shape and energy
    • The type of hybrid orbitals formed in a bonded atom depends on its electron-pair geometry as predicted by the VSEPR theory
    • Hybrid orbitals overlap to form σ bonds, unhybridized orbitals overlap to form π bonds
  • sp Hybrid Orbitals
    • The mixing of one s orbital and one p orbital forms two equivalent sp hybrid orbitals
    • According to the valence-bond model, a linear arrangement of electron domains implies sp hybridization
  • sp2 and sp3 Hybrid Orbitals

    • Three sp2 hybrid orbitals are formed from hybridization of one s and two p orbitals, with one unhybridized p orbital remaining
    • Four sp3 hybrid orbitals are formed from hybridization of one s and three p orbitals, with each of the four large lobes pointing towards the vertex of a tetrahedron
  • sp3d and sp3d2 Hybrid Orbitals

    • Five sp3d hybrid orbitals are formed from hybridization of one s, three p orbitals and 1 d orbital, arranging in a trigonal bipyramidal shape
    • Six sp3d2 hybrid orbitals are formed from hybridization of one s, three p orbitals and 2 d orbitals, arranging in an octahedral shape
  • To Assign Hybridization
    1. Draw a Lewis structure
    2. Assign the electron-domain geometry using VSEPR theory
    3. Specify the hybridization required to accommodate the electron domains based on their geometric arrangement
    4. Name the geometry by the positions of the atoms
  • σ and π bonding
    • Every pair of bonded atoms shares one or more pairs of electrons
    • Two electrons shared between atoms on the same axis as the nuclei are σ bonds, σ bonds are always localized in the region between two bonded atoms
    • If two atoms share more than one pair of electrons, the additional pairs form π-bonds
    • When resonance structures are possible, delocalization is also possible
  • Molecular Orbital Theory
    • Molecular orbitals are associated with an entire molecule, each contains a maximum of two electrons with opposite spins, each has a definite energy, electron density distribution can be visualized with contour diagrams
    • When two atomic orbitals (AO) overlap, two molecular orbitals (MO) form - a bonding MO and an antibonding MO
    • Sigma (σ) MOs have electron density in both molecular orbitals centered about the internuclear axis, the σ bonding MO is lower in energy than the σ* antibonding MO
    • Bond order = ½ (bonding electrons - antibonding electrons), BO = 1 for single bond, 2 for double bond, 3 for triple bond
    • The number of MOs = number of AOs, AOs of similar energy combine, as overlap increases, the energy of the bonding MO decreases and the energy of the antibonding MO increases
    • Pauli: each MO has at most two electrons, with opposite spins, Hund: for degenerate orbitals, each MO is first occupied singly before spin pairing occurs
    • Two ways p orbitals can overlap: end on (σ MO) or sideways (π MO)
  • Dissolution Process
    1. Intermolecular forces between solute and solvent particles
    2. Solute-solute interactions
    3. Solvent-solvent interactions
    4. Solvent-solute interactions
    5. Enthalpy change in solution process
  • gas constant R
    0.08206 L•atm/mol•K
  • Gas Pressure (9.1)

    Pressure is the force acting on an object per unit area: P = F/A
  • The formation of a solution is an example of a spontaneous process
  • Criteria that favor the spontaneous formation of a solution: decrease in internal energy, increased dispersal of matter
  • Units of pressure
    • pascal (Pa)
    • bar
    • atmospheres (atm)
    • millimeter of mercury (mm Hg) or torr
  • Dissolution and crystallization
    1. Solute + solvent → solution
    2. Solution → solute + solvent
  • Atmospheric pressure at sea level is about 100 kPa, or 1 bar, or 14.7 psi
  • Saturated solution
    Solution with a concentration of dissolved solute that is equal to the solubility
  • Standard atmospheric pressure is the pressure required to support 760 mm of Hg in a column
  • Bronsted-Lowry acid

    Species that donates H+
  • Manometer
    A device used to measure the pressure of a gas trapped in a container
  • Unsaturated solution

    Solution with a concentration of dissolved solute that is less than the solubility
  • Intermolecular forces
    The forces holding solids and liquids together
  • Bronsted-Lowry base

    Species that accepts H+
  • The first law of thermodynamics: energy is conserved
  • Supersaturated solution

    Solution with more solute dissolved than in a saturated solution
  • Conjugate acid-base pair
    Acid and its conjugate base, or base and its conjugate acid
  • Relating Pressure, Volume, Amount, and Temperature: The Ideal Gas Law (9.2)

    Four variables are needed to define the physical condition or state of a gas: T (temperature), P (pressure), V (volume), and n (number of moles of gas)
  • Intermolecular forces are much weaker than ionic or covalent bonds
  • ΔE
    Change in internal energy
  • Electrolyte
    Substance that undergoes a physical or chemical change to yield ions in solution
  • Strong acids completely transfer their protons to water
  • Amonton's or Gay-Lussac's Law

    The pressure of a given amount of gas is directly proportional to its temperature on the kelvin scale when the volume is held constant
  • Strong electrolyte
    Substance where the ion-producing process is essentially 100% efficient
  • q
    Heat absorbed by the system from the surroundings
  • Charles's law
    The volume of a fixed quantity of gas at constant pressure is directly proportional to its absolute temperature
  • Weak acids only partially dissociate in aqueous solution
  • w
    Work done
  • Boyle's law
    The volume of a fixed quantity of gas, at constant temperature, is inversely proportional to its pressure
  • Weak electrolyte
    Substance where only a relatively small fraction of the dissolved substance undergoes the ion-producing process
  • Melting points and boiling points

    Reflect the strength of attractive forces