Cards (42)

  • An extraterrestrial creature is standing in front of planemirror. The height of this creature is H and we know that thiscreature has eyes positioned h below the top of its head.This creature sees its reflection which fit exactly the mirror,it means, this creature can just see the top of head and thebottom of its feet (or whatever it uses for motion).We canconclude that the top of a mirror is exactly
    (H-h/2) above the ground
  • An extraterrestrial creature is standing in front of planemirror. The height of this creature is H and we know that thiscreature has eyes positioned h below the top of its head.This creature sees its reflection which fit exactly the mirror,it means, this creature can just see the top of head and thebottom of its feet (or whatever it uses for motion).We canconclude that the bottom of a mirror is exactly
    (H-h)/2 above the ground
  • An extraterrestrial creature is standing in front of planemirror. The height of this creature is H and we know that thiscreature has eyes positioned h below the top of its head.This creature sees its reflection which fit exactly the mirror,it means, this creature can just see the top of head and thebottom of its feet (or whatever it uses for motion).We canconclude that the minimum size of a mirror is exactly
    H/2
  • An extraterrestrial creature is standing in front of planemirror. The height of this creature is H and we know that thiscreature has eyes positioned h below the top of its head.This creature sees its reflection which fit exactly the mirror,it means, this creature can just see the top of head and thebottom of its feet (or whatever it uses for motion). Results of this question depend on...
    Do not depend on the distance between this creature and mirror
  • Light is traveling from the medium with index of refraction 1.4into the air and experiences total internal reflection. We canpredict that critical angle for light traveling from medium withn=1.4 into medium with n=1.2 will be
    Greater than for light traveling from medium n = 1.4 into air
  • We can predict that critical angle for light traveling from mediumwith n=1.4 into medium with n=1.6 will be
    There will be no critical angle
  • In some optical setup consisting of a single lens and an objectmagnification factor is measured as m=-0.5.we can conclude that this lens is:
    converging
  • In some optical setup consisting of a single lens and an objectmagnification factor is measured as m=-0.5.We can conclude that object in this particular setup is positioned:
    At distance greater than double focal length
  • In some optical setup consisting of a single lens and an objectmagnification factor is measured as m=-0.5. Distance to the image in this particular setup is?
    Is between focal length and doubled focal length
  • Consider an optical setup in which distance between object and viewing screen L is fixed. Aconverging lens of focal length f can be moved between object and screen, so that distance toobject and distance to image is varied. If the distance L between object and screen satisfies acondition L>4f, we can conclude that:
    There are two positions of a lens which provide sharp image of the object on a screen
  • Check how you understand the principles of working of eyeglasses (contactlenses). Eyeglasses (contact lenses) are used
    to create image of an object at the place convenient for the eye
  • Image distance for eyeglasses (contact lenses) is
    Always negative
  • If the far point of person’s eye is too short,to correct this we should use:
    Diverging lens
  • Consider layers of three media of different index of refraction.The thickness of layers is the same, say L. Medium A has indexof refraction 1.3; medium B has index of refraction 1.4 andmedium C has index of refraction 1.35. Light enters these layersnormally from the air. Rand these media in accordance the timeit takes for light to travel through these layers, greatest first:
    B, C, A
  • in a Young’s double slit experiment the width of a centralmaximum on a screen is:
    same as width of the second medium
  • Two lasers are illuminating the same system of double slitswith distance between slits 600 nm. One laser is red withwavelength 633 nm, another is green with wavelength 533 nm.We can conclude that
    Green Light produces interference pattern and red light pattern produces no interference pattern
  • Red laser is illuminating three sets of double slits, one afteranother. The wavelength of a laser is 633 nm, the distancesbetween slits are: 1500 nm; 900 nm; 600 nm. Which of thesesystems produces broader interference pattern on a screen?
    900 nm
  • Index of refraction of the top material is 1.2; index of refraction ofa film 1.3 and of the bottom material 1.4. For normal incidence thisfilm will look bright for light which wavelength satisfies thefollowing condition

    Thickness of a film is equal ½ of wavelength in the film.
  • Now index of refraction of the top material is 1.4; index of refraction of a film1.3 and of the bottom material still 1.2. For normal incidence this film willlook dark for light which wavelength satisfies the following condition
    Thickness of a film is equal ¼ of wavelength of light in the film
  • in a single slit diffraction experiment the width of acentral maximum on a screen is:
    Twice as broad as the width of the second maximum
  • Rectangular single slit has width in horizontal direction 1000nm and in vertical direction 1500 nm. We can conclude thatfor the red light
    Diffraction pattern is broader in horizontal direction
  • Consider three Polaroids, placed one after another. The firstone is illuminated by the unpolarized light of intensity I. Afterthis, light is falling on the Polaroid #2, 450 with the first one;after this light is falling on Polaroid #3, whose axis oftransmission is perpendicular to the axis of transmission ofPolaroid #1. Intensity of light after the Polaroid #3 is in termsof I:
    I/8
  • When a person stands 40 cm in front of cosmetic mirror, the direct image is twice the sizeof the object. What is focal length of the mirror?
    80 cm
  • Inverted image of some object is two times the size of the object. The image distance inthis optical setup is
    More than 2f and positive
  • Some object is approaching a concave mirror from infinity reaching finally distance tothe mirror equal to radius of curvature. While object is moving, image distance is
    Increasing in magnitude and positive
  • Image in some optical setup is direct and 1/3 of height of the object. We can make thefollowing conclusions about this particular setup:
    The mirror is convex, image is virtual
  • In some optical setup consisting on a single mirror and an object we measure themagnification factor m=+3. Distance to the image in this setup is:
    Negative and equal in magnitude to the radius of a mirror
  • When a person stands 40 cm in front of cosmetic mirror, the inverted image is twice thesize of the object. What is focal length of the mirror?
    27 cm
  • Inverted image of some object is half of the size of the object. The image distance in thisoptical setup is

    Between f and 2f and positive
  • Some object is moving away from the concave mirror from the focal point reachingfinally distance to the mirror equal to radius of curvature. While object is moving, imagedistance is
    decreasing in magnitude and positive
  • Image in some optical setup is inverted and 1/3 of height of the object. We can make thefollowing conclusions about this particular setup:
    The mirror is concave, image is real
  • In some optical setup consisting on a single mirror and an object we measure themagnification factor m=+2. Distance to the image in this setup is:
    Negative and less in magnitude than radius of the mirror
  • Distance between object and screen is fixed and equal 120 cm. The converging lens offocal length 35 cm is positioned between object and screen in attempts to get clear imageon the screen. Based on the data given we may conclude that:
    No position of the lens will provide sharp image on the screen
  • Distance between object and screen is fixed and equal 120 cm. The diverging lens offocal length 25 cm is positioned between object and screen in attempts to get clear imageon the screen. Based on the data given we may conclude that:
    No position of the lens will provide sharp image on the screen
  • Converging lens of focal length 24 cm is positioned into a setup with fixed distancebetween object and screen equal 100 cm. To create the sharp reduced image on the screenthe object distance should be:
    60 cm
  • Converging lens of focal length 24 cm is positioned into a setup up with fixed distancebetween object and screen equal 100 cm. To create the magnified image on the screen theobject distance should be:
    40 cm
  • Some object is moving away from the converging lens from the focal point reachingfinally distance to the lens equal to doubled focal length.. While object is moving, imagedistance is: (this question is the same as question #3 from the Quiz 12)
    Decreasing in magnitude and positive
  • A person has a near point 1 m. Contact lenses of what power should be prescribed forthem to read a book 25 cm from the eye?
    +3D
  • A person can clearly see between 20 and 30 cm from their eye. They got prescription(wrong one) for the lenses of power -2D. What is their far point with this lens in place?
    75 cm
  • What is the near point of the person from previous question with above mentioned lens inplace?
    33 cm