No recombination and want to get all parental types in the progeny of test cross
Incomplete linkage
there is recombination and it shows how to get recombination frequencies
Special type
Sex linkage (X linked, Y linked)
Test cross
An experimental cross, e.g. Dominant phenotype (PP or Pp) x recessive phenotype (pp)
independentassortment
If you have _ then the genes are located at different chromosomes (1:1:1:1)
Parentals >50% & Recombinants <50%
Genes are located on the same chromosome. The genes are linked
Linkage
linear arrangement of non-allelic genes (different locations on a chromosome) on the same chromosome ● genes do not assort independently ● genes can be separated by crossing-over (happens at pachynema)
complete linkage
Link genes are always transmitted together but that is more true if you have
There are cases when genes even though they are located at the same chromosome they are not transmitted together it will happen when crossing over took place
linkage
Three genes located at the same chromosome therefore we can say that these three are linked and do not assort independently and can onlyseparatedthrucrossingover
IndependentAssortment
located on different homologouschromosomes, one gene pair is assigned to a pair of homologous chromosomes
● Completelinkage
The genes are very close to each other thus transmitted together. - all parental types (100%) - no recombinant types (0%)
Incomplete linkage
● the genes are far from each other thus crossing-over is possible
Incomplete linkage
● recombinant types are obtained through crossing-over
Incomplete linkage
○ parental types >50% ○ recombinant types <50% (higher chance if higher frequencies of crossing over)
Linkage group
● physical association of genes on a chromosome ● number of linkage group is equal to the n (haploid no.)
Linkage in Drosophila
● published by Thomas Hunt Morgan in 1910
Linkage in Drosophilia
● X-linked traits in Drosophila ● confirmed the Chromosome Theory
Alfred Sturtevant, Herman Muller and Calvin Bridges
Who are the students of Morgan in 1915 that proposed the phenomenon of crossing-over, they also used linkage as tool for chromosome mapping?
X-linked mutants
● % recombination is used as a measurement of distance (How frequent recombination takes place between them)
X-linked mutants
one map unit or 1 cM (centimorgan) is the distance that gives 1% recombination
closer the gene
more difficult to break the linkage (lower frequency recombination)
Make a three-point test cross 2.Establish the proper gene order 3.Compute for the distance between genes – based on % recombination 4. Calculate for cc (coefficient of coincidence) 5. Solve for interference
What are the steps in gene mapping?
((SCO+DCO)/n)*100
formula for getting the % cross over at regions (COi)
Strength of linkage
measured by coefficient of coincidence (cc = highest value - 1, lowest value - 0 same with interference)
cc=ADCO/EDCO = (DCO/Total Progeny)/(COi)(COii)
formula for getting cc using adco and edco
(i) = 1 – cc
formula for interference
i = 1
there is complete interference (DCO are occurring as expected)
i = 0
there is no interference (DCO are not occurring as expected)
i > 0.5
near
i < 0.5
far
the closer the genes are, the lesser is the chance that crossing over will take place between them
Sex Linkage
sex chromosomes carry other genes aside from genes for sex determination
Sex Linkage
Genes are carried by sex chromosomes are not actually related to sex
X-linked Inheritance
can be due to sex-linked recessive genes (gene is carried by the x chromosome)
examples of x-linked inheritance
colorblindness - hemophilia - absence of central incisors - congenital deafness - congenital cataract (could be mother to son transmission)
Y-linked inheritance
- genes on the Y chromosome - father to son transmission
Y-linked Inheritance
shows holandric transmission
webbing of the toes ( 2nd and 3rd toes are attached) , hypertrichosis