Ideal Gas Equation

    Cards (24)

    • The volume of a gas at temperatures and pressures other than RTP can be calculated using the ideal gas equation.
    • The assumptions are:
      -Gases are made up of molecules which are in constant random motion in straight lines.
      -The molecules behave as rigid spheres.
      -Pressure is due to collisions between the molecules and the walls of the container.
      -All collisions, both between the molecules themselves, and between the molecules and the walls of the container, are perfectly elastic.
      -The temperature of the gas is proportional to the average kinetic energy of the molecules.
    • The 2 key assumptions:
      -There are no IMFs between the gas molecules.
      -The volume occupied by the molecules themselves is entirely negligible relative to the volume of the container.
    • The ideal gas equation is pV=nRT where p is the pressure, V is volume, n is the number of moles, R is the universal gas constant, and T is the absolute temperature
    • What does p represent in pV=nRT?
      Pressure.
    • What does V represent in pV-nRT?
      Volume.
    • What does n represent in pV-nRT?
      Amount of gas in mol.
    • What does R represent in pV-nRT?
      The ideal gas constant --> 8.314.
    • What does T represent in pV-nRT?
      Temperature.
    • What are the units of pressure in pV=nRT?
      Pa.
    • What are the units of volume in pV=nRT?
      m3m^3
    • What are the units of n in pV=nRT?
      mol
    • What are the units of R in pV=nRT?
      Jmol1K1J mol^-1 K^-1
    • What are the units of T in pV=nRT?
      Kelvin
    • What is the ideal gas constant?
      8.314 JK1mol1J K^-1 mol^-1
    • Pascals is the same as N/m^2 or N/m^3
    • 1m3=1m^3 =1000dm3= 1000dm^3 =1,000,000cm3 1,000,000cm^3
    • 0OC=0^OC =273K 273K
    • If given temperature in Celsius, add 273 to convert to Kelvin.
    • p=p =nRT/V nRT/V
    • V=V =nRT/p nRT/p
    • n=n =pV/RT pV/RT
    • T=T =pV/nR pV/nR
    • Calculate the pressure, in kPa, that a 2.05 mol sample of oxygen would exert if in a 52.3cm3 container at 1255K.
      = 4.09 x 10^5 kPa