In propagation step 2 a haloalkane, e.g. CH₃Br, is formed. Another halogen radical can collide with it, substituting another hydrogen atom to form dihaloalkane, e.g. CH₂Br₂. Further substitution can continue until all hydrogen atoms have been substituted.
The result is a mixture of CH₃Br, CH₂Br₂, CHBr₃, and CBr₄.