The study of the genetic composition of a population of organisms
Population
A group of organisms that actively interbreed and exchange a common set of genes (share a gene pool)
Why study population genetics?
Genotype frequency
How common is a particular genotype? (AA, Aa, or aa)
Allele frequency
How common is a particular allele? (A or a)
We usually can't study every member in a population, so we take a sample and use it to make predictions
The relationship between genotype frequency and allele frequency teaches us about the trait we're studying
If you don't understand the difference between genotype and allele frequency, you will get everything wrong in this part of the class
M/N blood type
LMLM = M-antigen on red blood cells
LNLN = N-antigen on red blood cells
LMLN = M-antigen and N-antigen on red blood cells
Co-dominance
In this case the phenotypes tell us genotypes, and we calculate both genotype frequencies and allele frequencies
Calculate allele frequencies from genotype numbers
1. p = frequency of LM in the population
2. q = frequency of LN in the population
In this case, since LM and LN are the only alleles in the population, p + q = 1
Calculate allele frequencies from genotype frequencies
1. p = f(M) = f(MM) + 1/2 f(MN)
2. q = f(N) = f(NN) + 1/2 f(MN)
Hardy-Weinberg Equilibrium
Under certain conditions (or assumptions), the relationship between allele frequencies and genotype frequencies will follow these rules:
Genotype Frequency
AA = p^2
Aa = 2pq
aa = q^2
Hardy-Weinberg frequencies are based on a set of assumptions
We can use those assumptions to estimate allele frequencies that we can't otherwise observe, or we can test whether a population is in HW equilibrium, to see if one or more of our assumptions are incorrect
Estimating allele frequencies at a locus
This assumes the population is in HW equilibrium with respect to the gene being studied, and uses the frequency of homozygous recessives to estimate the allele frequency in the population
Testing whether a population is in HW equilibrium with respect to a particular gene
This requires knowing the actual allele frequency in a population (not estimated), and uses chi-square test to see if genotype frequencies fit the predictions of HW equilibrium
Albinism
Frequency: 1/20,000
Assuming Hardy-Weinberg, chance that a random person is a carrier is 1.4%
Testing for equilibrium: χ2 goodness of fit test
1. Calculate the allele frequencies
2. Calculate the expected genotype numbers
3. Test whether our observed genotype numbers match the expected using a χ2 goodness of fit test
If a population is NOT in Hardy-Weinberg equilibrium, one (or more!) of the Hardy-Weinberg assumptions must be wrong
Hardy-Weinberg assumptions
Mating is random
No new alleles arise by mutation
There is no genetic exchange with outside populations
The population is large enough to avoid chance fluctuations
All genotypes are equally viable and fertile
Genotypes
LMLM
LMLN
LNLN
LMLM expected frequency
p^2 = 0.2911
LMLN expected frequency
2pq = 0.4968
LNLN expected frequency
q^2 = 0.2121
The population is in Hardy-Weinberg equilibrium
Population genetics
The study of the genetic composition of populations and how it changes over time
Hardy-Weinberg principle
A mathematical model that describes the genetic composition of a population and how it remains constant from generation to generation in the absence of evolutionary forces
Exceptions to Hardy-Weinberg
Nonrandom mating
Mutation
Gene flow
Genetic drift
Unequal fitness
Genetic equilibrium
A state where allele and genotype frequencies remain constant from generation to generation
If a population is NOT in Hardy-Weinberg equilibrium, one (or more!) of the assumptions must be wrong
Hardy-Weinberg assumptions
Mating is random
No new alleles arise by mutation
No genetic exchange with outside populations
Population is large enough to avoid chance fluctuations
All genotypes have equal survival and reproductive ability
Sickle cell anemia
Caused by 2 main alleles: HBBA (A) wild-type and HBBS (S) recessive mutant allele
Sickle cell genotypes
A/A: wild-type, normal blood
A/S: mostly unaffected, mild anemia
S/S: severe, often fatal anemia
The West African population study of 12,387 individuals does not fit Hardy-Weinberg equilibrium