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Chemistry 1
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Avogadro's number
There are
6.02
x 10^23 particles of a substance in
1
mole
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Mole
Unit used to measure the
amount
of a substance
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Moles
Mass
divided by
relative atomic mass
(M)
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Concentration in g/dm³
Mass
(g)
divided
by volume (dm³)
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Concentration
in mol/dm³
Moles
(mol) divided by volume (
dm³
)
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1 mole of any gas has a volume of
24dm³
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Converting from cm³ to dm³
1dm³
=
1000cm³
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Percentage Yield
Mass
of product actually made divided by maximum theoretical mass of product, multiplied by
100
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Atom Economy
Relative formula mass
of desired product from equation divided by sum of relative formula masses of all reactants from equation, multiplied by
100
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Calculating energy changes
Energy change in a reaction = Total energy needed to break the
bonds
in reactants - Total energy released when
bonds
in the products are formed
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Rate of
reaction
Mean rate of
reaction
= quantity of reactant used divided by time taken
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Chromatography
R<sub>f</sub> =
distance
moved by substance divided by
distance
moved by solvent
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Combustion
of carbon
Carbon
+
Oxygen
→ Carbon dioxide
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Combustion of hydrogen
Hydrogen
+
Oxygen
→ Water
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Combustion of hydrocarbons
Methane
+ Oxygen → Carbon dioxide +
Water
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Oxidation
of metals
Copper +
Oxygen
→
Copper
(II) oxide
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Displacement
of halogens
Sodium bromide +
Chlorine
→ Bromine +
Sodium chloride
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Reaction of metal with acid
Magnesium
+ Hydrochloric acid →
Magnesium chloride
+ Hydrogen
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Reaction of metal oxide with acid
Copper (II)
oxide
+ Hydrochloric acid → Copper (II) chloride +
Water
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Displacement
of
metals
Copper (II) sulfate +
Magnesium
→
Magnesium sulfate
+
Copper
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The Haber
process
Nitrogen
+ Hydrogen →
Ammonia
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Energy Reaction
Info
:
Calculating
the formula of a compound
1. Write the
element
symbols
2. Write the
masses
3. Write the
Ar values
4. Divide masses by
Ar
5. Divide by the
smallest
number
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Example
3.2 g of sulfur reacts with
oxygen
to produce 6.4 g of sulfur
oxide
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The
Ar
(relative atomic mass) of sulfur, S = 32, and the
Ar
of oxygen, O= 16
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Converting
the empirical formula to a molecular formula
1. Add up the
atomic
masses of the atoms in the empirical
formula
2. Divide the
relative
formula mass (Mr) by the
mass
of the atoms in the empirical formula
3.
Multiply
the
numbers
in the empirical formula by the result
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Percentage mass
A way of saying what proportion of the
mass
of the compound is due to atoms of that
element
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75% of the mass of
methane
is made up of
carbon
atoms, so if you have 100 g of methane, it will contain 75 g of carbon
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Calculating percentage mass
1. A, number of
atoms
of that
element
2. M,
mass
of the
compound
3.
Multiply
by
100
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The formula to calculate percentage mass is: Percentage
mass
of an element in a compound = (A, number of atoms of that element / M,
mass
of the compound) x 100
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Calculating the mass of a product
1. Write out the
balanced
equation
2. Work out the
relative formula
masses (M) of the limiting reactant and the product you want to find the mass of
3. Work out how many
moles
there are of the limiting reactant
4. Use the balanced equation to work out how many
moles
there'll be of the product
5. Use the number of
moles
, along with the relative formula
mass
of the product to calculate the mass
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3 x 2.54 =
7.62
g
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As
reactant'
is an important part of a reaction
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You can calculate the mass of a product formed in a reaction by using the
mass
of the
limiting
reactant and the balanced reaction equation
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At the same temperature and pressure, two moles of
chlorine
will also take up the same
volume
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24
g of oxygen (O2) will occupy
24
x 24 = 18 dm³ at room temperature and pressure (r.t.p. = 20 °C and 1 atm)
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Volume of gas (dm³)
Mass
of gas (g) / M, of gas ×
24
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Acid
Substance that forms
hydrogen
ions (H+) when dissolved in
water
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Alkali
Substance that forms
hydroxide
ions (OH-) when dissolved in
water
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Neutralisation reactions
Acid reacts with
alkali
to form
salt
and water
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See all 42 cards
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