What will happen to the voltmeter reading if light intensity decreases in series with a fixed resistor?
The resistance of the LDR increases as high intensity decreases. The resistance in the circuit increases.
The current in the circuit decreases because I=V/R, V is fixed in the circuit, R increases.
The p.d. across the fixed resistor decreases because the current decrease V=IR, R is fixed.
The p.d across the LDR increases because the p.ds have to up to the fixed EMF, Kirchoffs 2nd Law