Sample problem: Calculating heat absorbed by skin from 150 g steam at 100°C
1. Given: m = 150 g, c = 4.18 J/g°C, ΔT = 63°C
3. Solution: Q = (150 g)(4.18 J/g°C)(63°C) = 39,501 J
4. Heat absorbed = mΔHvap = (150 g)(2260 J/g) = 339,000 J
5. Total Q = 39,501 J + 339,000 J = 378,501 J