Arrangement of bonds around each carbon atoms in an alkane.
Each carbon atom forms four single bonds.
4 regions of election density
Equal electron pair repulsion
109.5 degrees bond angles
A tetrahedral arrangement around the carbon atoms
The effect of increasing chain length on the boiling point of alkanes
As the carbon chain increases means more electrons are present, creating stronger temporary induced dipoles, which increases the strength of London forces between molecules.
Also the surface contact between molecules increases, which increases the strength of London forces which require more energy to overcome.
The effect of branching on the boiling point of alkanes
The branched alkanes cannot pack closely together which means less surface contact between molecules. This leads to weaker London forces between molecules, which require less energy to overcome.
Why are alkanes described as being saturated?
The carbon atoms in alkanes are joined together by single covalent bonds
Why are alkanes used as fuels?
Release a large amount of energy when they undergo combustion
What is combustion?
Combustion is the reaction between a fuel and oxygen, resulting in the release of energy as heat.
What is the difference between complete and incomplete combustion
In complete combustion, there is a plentiful supply of oxygen, the fuel reacts completely to form carbon dioxide and water vapour.
In incomplete combustion, there is an insufficient supply of oxygen, the fuel doesn't react completely, producing carbon monoxide and water vapour.
It also produces solid carbon (soot)
Why does incomplete combustion occur?
When there is insufficient supply of oxygen for the fuel to react completely.
Longer chain alkanes need more oxygen compared to shorter chains.
Word equation of the complete combustion of a hydrocarbon:
Hydrocarbon + oxygen ----> carbondioxide + water
Products that can be formed during incomplete combustion of alkane:
Carbon Monoxide
Carbon
Water vapour
Unburnt hydrocarbon
Why is Carbon Monoxide harmful?
Is poisonous as it can prevent oxygen from binding to haemoglobin in the blood.
Why do alkanes have a low reactivity?
The strong C-C and C-H covalentbonds require a lot of energy to break.
The non-polar nature of C-C bonds make it difficult for alkanes to attract nucleophiles or electrophiles.
What is a free radical?
A free radical is a species with an unpaired electron (represented by a dot)
The unpaired electron in free radicals makes them very reactive.
Steps in a Free radical substitution mechanism:
Initiation (forming the radicals)
Propagation (repeated reactions that regenerates the free radical)
Termination (when two free radicals combine to form a stable product)
General equation for the reaction between an alkane and a halogen:
The conditions that are required for alkanes molecules to undergo reactions with halogens (S/E)
Alkanes react with halogens when exposed to UV light.
The energy from the UV light is enough to breaks the halogen - halogen bond which forms the radicals, which initiate the reaction.
What type of reaction occurs when alkanes react with halogens?
Free Radical Substitution
E.G. What is the equation for the initiation step in the reaction between methane and chlorine?
Cl2 ---> *Cl + *Cl
Two free radicals are formed
What type of bond fission occurs during the initiation step of the free radical substitution reactions?
Homolytic Fission
E.G. How does the relative amount of chorine and methane present determine the identity and ratio of products produced in the reaction between CH4 AND Cl2
If methane is in excess, more CH3Cl will be produced
If chlorine is in excess, further substitution of H with Cl may take place to form CH2Cl2, CHCl3, CCl4
Limitations of radical substitution reactions in organic synthesis? (S/E)
Free radical substitution leads to a mixture of products being formed as a result of:
Further substitution at the same position in the carbon chain.
Substitution at different position in the carbon chain.
E.G. Two equations for possible propagation steps in the reaction between methane and chlorine.
*Cl + CH4 ----> HCL + *CH3
*CH3 + Cl2 -----> CH3Cl + *Cl
E.G. Three equations for possible termination steps in the reaction between methane and chlorine.