Cards (20)

    • Redox titration
      oxidising agent is titrated against a reducing agent
    • potassium manganate (VII) titrations
      MnO₄⁻ is the oxidising agent
      • it is reduced to Mn²⁺
      • -1 —> 2+
    • potassium manganate (VII) titrations
      Iron (Fe²⁺) is the reducing agent
      • it is oxidised to Fe³⁺ (aq)
    • Potassium Manganate (VII) titration
      the reaction mixture must be acidified so excess acid is added to the iron (II) ions before the reaction starts
      • acid must not react with the manganate (VII) ions
      • acid provides the protons but doesn’t oxidise in these conditions
      • acid is typically dilute sulfuric acid
    • Potassium Manganate (VII) Titrations
      the titration is self indicating
      • reacts and decolourises as it is being added
      • end point is when the permanent pink colour forms
    • how many times do you repeat a titration?
      until you get concordant results
    • KMnO₄ is a deep purple
      • burette readings are taken from the top as it is difficult to see the bottom of the meniscus
    • procedure of the Potassium Manganate (VII) Titration
      1.) prepare 250 cm³ solution of impure FeSO₄ • 7H₂O in a volumetric flask
      2.) using a pipettes measure 25 cm³ of this solution into a conical flask
      3.) add 10 cm³ of 1 moldm⁻³ of H₂SO₄ (aq) (this is in excess)
      4.) using a burette titrations the solution
      5.) determine percentage purity
    • percentage purity
      mass of compound / mass of impure sample x 100
    • most transition metal ions naturally change colour when changing oxidation states
    • Procedure of Iodine-Thiosulfate titrations
      1.) add standard solution of Na₂S₂O₃ to a burette
      2.) prepare solution of the oxidising agent and add using a pipettes to a conical flask
      • add excess potassium iodide
      3.) titrate the solution with Na₂S₂O₃ (aq)
    • Idodine-Thiosulfate titrations
      add excess potassium iodide as that is the oxidising agent that reacts the iodide ions
      • produces iodine which turns the solution a orange-brown colour
    • Iodine-Thiosulfate titrations
      when titrated iodine is reduced back to I ⁻ and the brown colour fades gradually
      • this makes it difficult to see the end point
      • add starch indicator to clarify the end point
    • determining the end point in the Iodine-Thiosulfate titrations
      when the end point is being approached the iodine fades to be a straw colour
      • add starch indicator at this point
      • solution turns blue-black and as the iodine reactions ( when more sodium thiosulfate is added) the blue-black colour fades
      • end point is when the blue-black colour disappears
    • analysis of copper
      copper 2+ ions are produced by dissolving the compound in water
    • analysis of coper
      insoluble copper (II) compounds can be reacted with acids to form copper 2+ ions
      • for alloys like brass, react with concentrated nitric acid
    • why would hydrochloric acid not suitable for the redox titration?
      can be oxidised to chlorine gas (by Manganate VII ions)
    • why would nitric acid not be suitable for the redox reaction?
      is an oxidising agent and may oxidise the substance being analysed
    • why would ethanoic acid not be suitable for the redox titration?
      weak acid and the concentration of hydrogen ions will be insufficient
    • why would concentrated sulfuric acid not be suitable for the redox titration?
      may oxidise the substance being analysed