The reaction of halide salt with concentrated sulphuric acid

Cards (5)

  • Fluoride and chloride
    F- and Cl- ions are not strong enough reducing agents to reduce the S in H2SO4. No redox reactions occur. Only acid base reactions
    NaF (s) + H2SO4 (l) --> NaHSO4 (s) + HF (g)
    • Observations is white steamy fumes of HF forming
    NaCl (s) + H2SO4 (l) --> NaHSO4 (s) + HCl (g)
    • Observations is white steamy fumes of HCl forming
  • Bromide
    Br- ions are stronger reducing agents then Cl- and F- and after initial acid base reactions, it reduces the sulphur from +6 to +4.
    Acid base reaction
    • NaBr (s) + H2SO4 (l) --> NaHSO4 (s) + HBr (g)
    • Observations is white steamy fumes of HBr are evolved
    Redox step
    • 2HBr + H2SO4 --> Br2 + SO2 + 2H2O
    • Observations is red fumes of bromine are evolved as well as a colourless and acidic gas sulphur dioxide
  • Bromide pt2 half equations
    Oxidation
    • 2Br- → Br2 + 2e-
    Reduction
    • H2SO4 + 2H+ + 2e- → SO2 + 2H2O
  • Iodide pt1
    I- ions are the strongest halide reducing agents
    NaI (s) + H2SO4 (L) --> NaHSO4 (s) + HI (g)
    2HI + H2SO4 --> I2 (s) + SO2 (g) + 2H2O ( L)
    6HI + H2SO4 --> 3I2 + S (s) + 4H2O (L)
    8HI + H2SO4 --> 4I2 + H2S (g) + 4H2O (L)
  • Iodide pt2
    They can reduce sulphur in H2SO4 from +6 to +4 in SO2 , to 0 in S and to -2 in H2S
    Observations:
    • White steamy fumes of HI are evolved
    • Black solid and purple fumes of iodine are also evolved
    • A colourless, acidic SO2
    • A yellow solid of sulphur is produced
    • H2S a gas with a bad egg smell