Acronym for the French "Système International d'Unités"
Mass
An invariant measure of the quantity of matter in an object
Weight is the force of attraction between an object and its surroundings, principally the earth
A chemical analysis is always based on mass so that the results will not depend on locality
Mole
The SI unit for the amount of a chemical substance
Always associated with specific microscopic entities such as atoms, molecules, ions, electrons, other particles, or specified groups of such particles as represented by a chemical formula
Avogadro's number NA = 6.022 x 10^23
Molar mass M is the mass in grams of 1 mole of that substance
Millimole
1/1000 of a mole, and the mass in grams of a millimole, the millimolar mass (mM), is likewise 1/1000 of the molar mass
Calculating moles and millimoles
1. Moles: n = m/M
2. Millimoles: mmol = m/mM
Sample Problem #1
Find the number of moles and millimoles of benzoic acid (M = 122.1 g/mol) that are contained in 2.00 g of the pure acid
Sample Problem #2
What is the mass in grams of Na+ (22.99 g/mol) in 25.0 g of Na2SO4 (142.0 g/mol)?
Molar concentration
The number of moles of a solute species that is contained in 1 liter of the solution (not 1 L of the solvent)
Unit is molar, symbolized by M, which has the dimensions of mol/L, or mol-L-1
Also the number of millimoles of solute per milliliter of solution
Sample Problem #3
Calculate the molar concentration of ethanol in an aqueous solution that contains 2.30 g of C2H5OH (M=46.07 g/mol) in 3.50 L of solution
Molar analytical concentration
Gives the total number of moles of a solute in 1 liter of the solution
Specifies a recipe by which the solution can be prepared regardless of what might happen to the solute during the solution process
Molar equilibrium concentration
The molar concentration of a particular species in a solution at equilibrium
Requires knowing how the solute behaves when dissolved in a solvent
Sample Problem #4
Calculate the analytical and equilibrium molar concentrations of the solute species in an aqueous solution that contains 285 mg of trichloroacetic acid, Cl3CCOOH (163.4 g/mol), in 10.0 mL (the acid is 73% ionized in water)
Preparing solutions
1. Sample Problem #5: Describe the preparation of 2.50 L of 0.120 M BaCl2 from BaCl2 ⋅ 2H2O (244.3 g/mol)
2. Sample Problem #6: Describe the preparation of 500 mL of 0.0740 M Cl- solution from solid BaCl2 ⋅ 2H2O (244.3 g/mol)
Weight percent (w/w)
Weight solute / weight solution x 100%
Volume percent (v/v)
Volume solute / volume solution x 100%
Weight/volume percent (w/v)
Weight solute (g) / volume solution (mL) x 100%
The denominator in each percent concentration expression is the mass or volume of solution rather than mass or volume of solvent
Weight percent is often used to express the concentration of commercial aqueous reagents
Weight/volume percent (w/v)
Weight solute, g / Volume solution, mL x 100%
The denominator in percent concentration expressions is the mass or volume of solution rather than mass or volume of solvent
Weight percent
70% (w/w) nitric acid solution
Volume percent
5% (v/v) aqueous methanol solution
Weight or volume percent
5% (w/v) aqueous silver nitrate solution
Parts per million (ppm)
Concentration expressed as parts per million
Parts per billion (ppb)
Concentration expressed as parts per billion
Parts per thousand (ppt)
Concentration expressed as parts per thousand
Calculating molar concentration from ppm
1. Convert ppm to moles
2. Divide moles by volume to get molar concentration
Solution-diluent volume ratio
Composition specified as volume of concentrated solution : volume of solvent
Solution-diluent volume ratio
1:4 HCl solution
value
Negative logarithm (base 10) of molar concentration
Calculating p-value
Take negative logarithm (base 10) of molar concentration
Calculating molar concentration from p-value
Take antilog (base 10) of negative p-value
Density
Mass per unit volume
Specific gravity
Ratio of mass to mass of equal volume of water at 4°C
Calculating molar concentration from density and weight percent
1. Convert weight percent to mass
2. Divide mass by molar mass to get moles
3. Divide moles by volume to get molar concentration
Stoichiometry
Quantitative relationship among amounts of reacting chemical species
Empirical formula
Simplest whole number ratio of atoms in a chemical compound
Molecular formula
Specifies the number of atoms in a molecule
Structural formula
Reveals structural differences between compounds with the same molecular formula