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Mole concepts
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Relative atomic mass
(Ar)
The
average
mass of one atom of an element compared to 1/12 of the mass of one
carbon-12
atom
Relative atomic mass
has no unit
Relative atomic mass of an element can be found in the
Periodic Table
Relative molecular mass
(Mr)
The
average
mass of one molecule of an element or compound compared to 1/12 of the mass of one
carbon-12
atom
Relative
molecular mass
is the sum of the
Ar
of all the atoms in a molecule
Relative
molecular mass
has
no
unit
Relative formula mass
A more accurate way to refer to the Mr of ionic compounds, since ionic compounds do not exist as
molecules
Relative formula mass
is calculated in exactly the same way as
relative molecular mass
Relative
formula mass
has
no
unit
Calculating relative molecular mass
Mr of carbon dioxide CO2 =
12
+ (2 ×
16
) = 44
Mr of sodium chloride NaCl = 23 + (1 ×
35.5
) =
58.5
Mr of hydrated magnesium sulfate, MgSO4 • 7H2O = 24 + 32 + (4 ×
16
) + (7 x 18) =
246
Mole
(mol)
Used to count the number of particles (atoms,
molecules
,
ions
and even sub-atomic particles such as
electrons
)
One mole of any substance will always contain
6.02
×
1023
particles of that substance
This is also known as the
Avogadro's constant
Avogadro's Number
1
mol of hydrogen atoms contains 6.02 ×
1023
hydrogen atoms
1
mol of water contains 6.02 ×
1023
water molecules
1
mol of CuSO4 contains 6.02 ×
1023
formula units of CuSO4
1 mol of Na+ ions contains
6.02
×
1023
Na+ ions
1 mol of O2 contains
2
mol of oxygen atoms
1
mol of O3 contains
3
mol of oxygen atoms
Molar mass
The
mass
of one mole of atoms of an
element
(g/mol)
The
mass
of one mole of
molecules
of a substance (g/mol)
The
mass
of one mole of formula units of an
ionic
compound (g/mol)
Calculating moles and molar mass
Number of
moles
of
iron
= 196 g / 56 g/mol = 3.5 mol
Number of moles of
NH3
=
4.25
g / 17 g/mol = 0.25 mol
Mass
of
0.5
mol of MgO = 0.5 mol × 40 g/mol = 20 g
Avogadro's Law
Equal volumes of all
gases
, under the same temperature and pressure, contain the same number of particles, hence have the same number of
moles
One mole of any gas occupies a volume of
24
dm3 at room temperature and
pressure
Calculating moles and volume of gases
Number of
moles
of
CO2
in 3 dm3 = 3 dm3 / 24 dm3/mol = 0.125 mol
Volume of
0.75
mol of CH4 = 0.75 mol ×
24
000 cm3/mol = 18 000 cm3
Volume of 4 g of O2 = (4 g / 32 g/mol) ×
24
dm3/mol = 3
dm3
Concentration of a solution
The amount of
solute
(in g or mol)
dissolved
in 1 dm3 of a solution
Can be expressed in
g/dm3
or
mol/dm3
Calculating concentration of a solution
Concentration of
9.6
g NaOH in 100 cm3 =
9.6
g / 0.1 dm3 = 96 g/dm3
Concentration of 9.6 g NaOH in 100 cm3 =
96
g/dm3 / 40 g/mol =
2.4
mol/dm3
Balanced
chemical
equation
Provides information on reactants, products,
mole ratio
, and
physical state
of each reactant and product
Stoichiometry
The relationship between the number of
moles
of reactants and the number of
moles
of products involved in a chemical reaction
Procedure for chemical calculations
1. Construct a
balanced
chemical equation
2. Find the number of
moles
of the given substance
3. Compare the
mole ratio
of the given substance to that of the unknown substance
4. Calculate the number of
moles
of unknown substance
The volume of one mole of any gas is
24
dm3 at room temperature and
pressure
(r.t.p.)
Information provided by a balanced chemical equation
Reactants
Products
Mole ratio
Physical state
of each reactant and product
A balanced chemical equation enables us to calculate the
mass
, volume and number of
moles
of reactants or products
Mole ratio
The ratio of the number of moles of the
reactants
and
products
Molar mass
The mass of
one mole
of a substance
Steps to calculate the mass of magnesium chloride formed
1. Find the number of
moles
of magnesium
2. Refer to the balanced chemical equation to find the mole ratio of
magnesium
to
magnesium chloride
3. Calculate the
mass
of
magnesium
chloride produced
Steps to calculate the mass of oxygen combined with 46g of sodium in sodium oxide
1. Find the number of
moles
of sodium
2. Use the mole
ratio
of sodium to
oxygen
in the compound formula
3. Calculate the number of
moles
and
mass
of oxygen
Steps to calculate the maximum mass of potassium that can be extracted from 188g of potassium oxide
1. Find the number of
moles
of potassium oxide
2. Use the mole ratio of
potassium oxide
to
potassium
in the compound formula
3. Calculate the number of
moles
and
mass
of potassium
Avogadro's law
The volume of a gas is proportional to the number of
moles
of the
gas
, and vice versa
Steps to calculate the volume of ammonia gas produced
1. Find the mole ratio of
nitrogen
to
ammonia
from the balanced equation
2. Use the mole ratio to calculate the
volume
of
ammonia
produced from a given volume of nitrogen
Steps to calculate the volume of oxygen gas required for complete combustion of methane
1. Find the mole ratio of
methane
to
oxygen
from the balanced equation
2. Use the mole ratio to calculate the volume of
oxygen
required from a given volume of
methane
Titration
A method of
volumetric
analysis used to determine the
concentrations
of solutions
Steps to solve a titration problem
1. Write the
balanced
chemical equation
2. Calculate the number of
moles
of the acid used
3. Find the
concentration
of the
alkali
in mol/dm3
4. Convert the
concentration
in mol/
dm3
to g/dm3
Example 1
1. Write the
balanced
chemical equation for this reaction
2. Calculate the number of
moles
of hydrochloric acid used
3. Find the
concentration
of sodium hydroxide in mol/dm3
4. Find the
concentration
of sodium hydroxide in g/dm3
Concentration
Solution concentration in
mol/dm3
or
g/dm3
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