forces and elasticity

Cards (9)

  • Change of shape
    When a force acts on an object, the object may change shape by bending, stretching or compressing.
  • there must be more than one force acting to change the shape of a stationary object in the following ways:
    • Bend an object's ends past each other, eg when an archer pulls an arrow back against a bow.
    • Pull an object's ends apart, eg when a rubber band is stretched.
    • Push an object's ends together, eg when an empty drinks can is squashed.
  • A change in shape is called deformation:
    • elastic deformation = reversed when the force is removed
    • inelastic deformation = not fully reversed when the force is removed - there is a permanent change in shape
    A rubber band undergoes elastic deformation when stretched a little.
    A metal drinks undergoes inelastic deformation when it is squashed.
  • Hooke's law
    The extension of an elastic object (such as a spring) is directly
    proportional to the force applied, provided that the limit of
    proportionality is not exceeded.
  • force = spring constant × extension
    F = k e
    force, F, in newtons, N
    spring constant, k, in newtons per metre, N/m
    extension, e, in metres, m
  • Work is done when...
    a spring is extended or compressed. 
    • Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened
    • the work done is equal to the elastic potential energy stored.
  • Linear extension and non-linear extension
    • Non-linear extension and inelastic deformation can be seen above the limit of proportionality. The limit of proportionality is also described as the 'elastic limit'.
    • Linear extension and elastic deformation can be seen below the limit of proportionality
    • The gradient of a force-extension graph before the limit of proportionality is equal to the spring constant.
  • calculate work done in stretching (or compressing) a spring
    (up to the limit of proportionality) using the equation:
    elastic potential energy = 0.5 × spring constant × extension 2
    Ee = 1/2 k e2
  • required practical
    1. Clamp stand, two bosses and two clamps - place a heavy weight on clamp stand to stop it falling over
    2.  Attach a metre ruler and a spring (ruler at the 0 point) 
    • Metre ruler should be vertical or readings will be inaccurate 
    • End of spring has a point and this should be horizontal (gives us readings)
    1. Mean the pointers current positive (the unstretched length with no force attached) 
    2. Add a 1N weight and read position of pointer, repeat process taking down the readings 
    3. To work out the extension, subtract length of the unstretched length from the reading