Down the group of halides, reducing power increases.
This trend is explained by the increasing number of electron shells.
This causes the distance between the outer electrons and the nucleus to increase, so that attraction decreases.
Therefore, the electron is more easily lost and donated to another atom which reduces that atom.
Down the group, the ability of the halogens to act as an oxidising agent decreases
This makes F2, Cl2 and Br2 stronger oxidising agents than I2.
Therefore, F2, Cl2, Br2 will oxidise I− to I2.
acid-base reaction when sodium bromide reacts with concentrated sulfuric acid
NaBr (s) + H2SO4 (l) → NaHSO4 (s) + HBr (g)
At room temperature:
Fluorine→a pale yellow gas
Chlorine→pale green gas
Bromine→a red-brown or red or brown liquid
Iodine→is a solid with a black colour
Astatine→is a solid
As you go down group 7
full shells → increases
shielding → increases
atomic radius → increases
distance between shared electron pair and nucleus → increases
Explain trend in boiling point
Boiling point increases down the Group 7 halogens (fluorine to iodine) due to increased London dispersion forces
Halogens act as → oxidising agent
Bromine displaces → Iodide
Chlorine displaces → Bromide and Iodide
Fluorine displaces → Chloride, Bromide and Iodide
Which halogens oxidise iodide ions to iodine? F, Cl, Br
What is added to test halide ions in an aqueous solution → Silver nitrate (AgNO3) solution
Identifying Halides using Silver Nitrate
silver fluoride → no precipitate
silver chloride → white colour precipitate
silver bromide → cream coloured precipitate
silver iodide → yellow coloured precipitate
Why does AgF form no precipitate → AgF is soluble in water
What can cause impurities in the halide solution → any carbonate and hydroxide ions as will form precipitates with silver nitrate, giving a false positive result
How can we get rid of impurities in the halide solution → acidfy it with dilute nitric acid