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Module 2 Foundations in chemistry
amount of substance
moles and volumes
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Cards (23)
Standard
solution
A solution of known
concentration.
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Concentration
The amount of
solute
, in
moles
, dissolved in
1
dm³ (
1000
cm³) of solution
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Molar gas volume, V
The
volume
per
mole
of
gas
molecules at a stated
temperature
and
pressure
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Mole
The amount of any substance containing as many
elementary
particles as there are
carbon
atoms in exactly
12
g of the carbon-12 isotope, i.e.
6.02
x 10^23 particles
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Avogadro constant N
6.02
x 10^
23
mol-1, the number of atoms per
mole
of carbon-12
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ideal gas equation
pV
=
nRT
what is R in pV = nRT?
gas constant
ideal gas equation units
p =
pressure
(
Pa
)
V =
volume
(
m3
)
n =
moles
(
mol
)
R =
gas
constant
T =
temperature
(
K)
gas constant, R
8.314
to convert cm3 to m3 you must
multiply
by 10^
-6
to convert dm3 to m3 you must
multiply
by
10
^
-3
to convert from celsius to kelvin +
273
kPa
to
Pa
x 1000
1 dm3 =
1000
cm3 =
1000
ml = 1 litre
RTP is
20C
and
101kPa
(1 atm) pressure
At RTP 1 mole of gas molecules has a volume of approx
24
dm3 =
24,000
cm3
Molar gas volume at RTP is
24
dm3 mol-1
mol = volume/
molar
gas
volume
when the volume (V) is in dm3, divide volume by
24
when the volume (V) is in cm3, divide volume by
24,000
moles
(
n
) =
concentration
(
c
) x
volume
(
V
)
You will usually measure volumes in cm3 so you will need to convert into dm3 by
dividing
by
1000
To work out the
mass concentration
(g dm-3) , you need to convert between
moles
and grams. So do moles x
Mr
= mass