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Math Grade 9
Math Quarter 3
Fundamental Theorems on Proportionals
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Kai Ignacio
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Cards (27)
Proportion
An equation that shows two
ratios
are
equal
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Proportion
Can be written in
column
form or
fraction
form
Denominator
(b) should not be equal to zero
Denominator
(d) should not be equal to zero
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Terms of a
proportion
a,
b
,
c
, d
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Means
b
and
c
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Extremes
a and
d
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Checking if a pair of ratios form a proportion
1. Product of the means is
equal
to the product of the
extremes
2.
Cross multiplication
(ad = bc)
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Solving for a missing value in a proportion
1.
Cross multiplication
(ad = bc)
2.
Dividing
both sides
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Similar triangles
Corresponding angles are
congruent
Corresponding sides are
proportional
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Deriving proportions from similar triangles
Using the basic
proportionality
theorem
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Finding a missing length in a triangle
1. Applying the basic
proportionality
theorem
2. Using properties of proportions (multiplication, inverse,
reciprocal
,
addition
, subtraction)
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Multiplication
1. Multiply e times
15
2. Multiply
12
times
10
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Multiplying the means and the extremes
15
times de is equal to
12
times 10
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Solving the equation
1. Divide both sides by
15
2. de is
120
divided by
15
, which is 8
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There are
two
ways of solving the equation
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12
over 8 is equal to
15
over 10
They are
proportions
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Proportions
When the
simplest
form of the fractions are equivalent, they are
proportions
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The answer is
correct
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Triangle ABC
AD is
5
cm
BD is x +
6
cm
AE is
3
cm
EC is x +
3
cm
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Finding the value of x
1. Set up a
proportion
: AD/DB =
AE/EC
2. Solve the equation to find x =
1.5
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Triangle ACD
DB is
3x
+
1
BC is
3x
-
1
AE is
5x
-
1
EC is
4x
+
1
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Finding the value of x
1. Set up a
proportion
: DB/BC = AE/EC
2. Solve the equation to find x =
5
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The value of x cannot be
0
as it would result in
negative
measurements
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Triangle QRS
RD is
3
cm
DQ is
5
cm
RS is
12
cm
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Finding the value of RE
1. Set up a
proportion
: RD/RQ = RE/RS
2. RE is
9/2
cm
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Trapezium ABCD
AB is
parallel
to DC
P and Q are points on AB and DC
PD is
18
cm
BQ is
35
cm
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Finding the value of PA
1. Set up a
proportion
: DP/PA = CQ/QB
2. PA is
42
cm
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The
triangles
are similar, so their corresponding
angles
are congruent and their corresponding sides are proportional
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