How will they ask about this?

• What to remember when they ask: "Describe the pathway taken by light when forming an image on the retina"?

  • HOW: speak about light moving through all the structures the light passes through
  • WHEN: you view an object in the light
  • WHERE: image forms on retina and electrical impulse is created and sent via the optic nerve to the occipital lobe
• Where is the light stimulus converted to an impulse?

  The retina
• Name the visual defect observable in the diagram: look for the point of focus, and then identify if it is myopia or hypermetropia.
• Strong Base Acid Strong Acid strong base H20 weak ions Base * exception 1 Ht 2 Ht 3 H: · Fet, Fet Anions · p62 [CH3COOH I I -] (00H)2 Bases Acids ↓ Nat NOs Nat + HNO3 NaNOs + H2O H NO, Nat 02 Nat NO5 NacO + HNO3 - NaNO3 + H2O H + NO2 kt OH g KOH + H2SO4 K2SOx + H20 H SO2 Ca CO2 + - Hacoo lat CaCO3 + CH3COOH > (CH3COO HtSalts /BasicNeutralization: Acid reacts with base, neither are in excess -pinette 17 drops - still clear basilization dropa Pi cacidic Titration no excess End-point no limiting reagent Equivalent point "reacted completely" standard Solution: solution with an exact known concent
• Base Neutralization: Base Neutraliz.
• Before dilution, the concentration of NaOH is 0 mol/L and after dilution, it is 0.31 mol/L.
• Before dilution, the concentration of H2SO4 is 80008 mol/L and after dilution, it is 8800 mol/L.
• In a neutralization reaction, the concentration of H2SO4 remains the same before and after dilution.
• In a neutralization reaction, the concentration of NaOH changes from 0 mol/L to 0.31 mol/L after dilution.
• Acid Limiting reagent Excess Base Acidic excess Acid Base Basic excess Acid excess excess Neutralized Neutralizedcomplete cer COR reaction ↓ Base Acid E2: H2SOy (Acid) NaOH (Base) c = = = -mol.dm, a = 0,25 -V = 0,025dm3 > V = 0,040 din 0,25 E0 - 0 (Neutralization) (C = 0.25 moldr3 < C = ? 0.00625 mol Nat SO4-0,0125 mol na I Ca Va c NaOH + H2SO4 NacSO4 + 2H20 nb Cb Vb Base: Acid H2SOy: NaOH 10,25) (0,025) ↓ 1 : 2 os5 e2 = (b(0.04) 2: I 0.00625 : 0,0125 (b = 0,31 mol.dm-3 H2SO4 Rc(NaOH) = = 0,0125 c = A;0,25 = 0.025 0.04 n(H2SO4) = 0,00625 mol <(NaOH) = 0.31 mol.dm-3 the art of concentrati