Gibbs free energy and entropy

Cards (17)

  • entropy is the degree or measure of disorder/ randomness (S)
  • solid is more ordered than liquids. liquids are more ordered than gases - GASSES ARE THE MOST DISSORDERED
    • H20(s) = 48 JK-1 mol-1
    • H20(l) = 70 JK-1 mol-1
    • H20(g) = 189 JK mol-1
  • the HIGHER the entropy value = the HIGHER degree of disorder of a substance
  • crystalline solid = highly ordered arrangement; low entropy
    melts becoming less ordered = entropy increases
    • ordered metallic and ionic lattice = Low ENTROPY
    • melting point (s to l) there is a large increase in disorder
    • boiling point (l to g) there is a very large increase in disorder as the atoms are more far apart from each other
  • the higher the mr value of the substance in the SAME state = the higher the entropy value
    • H2 (g) = 131 Jkmol CO2 (g) = 214 JKmol
    mr= 2 mr= 44
  • entropy change = sum of entropy values of products - sum of entropy values of reactants
  • determining entropy:
    1. how much DISORDER there is aka the state
    2. DISSOLUTION = if the solid is able to dissolve it increases its disorder so entropy increases
    3. AMOUNT OF PARTICLES = more particles mean more entropy as there are more ways their energy can be arranged
  • free energy change (ΔG) is a measure used to predict whether a reaction is feasible
  • feasible reaction is one that once started will carry on to completion without any energy being supplied to it
  • feasibility of a reaction depends on:
    • enthalpy change of a reaction
    • entropy change of a reaction
    • temperature at which reaction is occurring
  • If  free energy change (ΔG) is 0 or negative = reaction is FEASIBLE
  • free energy change [ΔG] = enthalpy change [ΔH] – (temperature x entropy change [ΔS])
  • units for: ∆G = ∆H - T∆S
    • ΔG = J mol-1
    • ΔH = J mol-1
    • T = K
    • ΔS = J K-1 mol-1
    ensure units are consistent so to convert KJ into J we x1000
  • when working out minimum temperature for a reaction to become feasible you must convert ∆G = ∆H - T∆S
    • T = ∆ H / ∆ S
    we assume ∆G is 0
  • for a reaction to be feasible (temp x entropy change) part of the equation must be BIGGER than (enthalpy change)
  • free-energy graphs: ∆G vs T
    the graph is a straight line so can use y = mx + c rearranged
    • gradient (m) = -entropy change {-∆S}
    • y - intercept (c) = enthalpy change {∆H}
    equation
    ∆ G = (-∆ S x T) + ∆ H