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physical chemistry 2
8. Thermodynamics
Gibbs free energy and entropy
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Nayana Mistry
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entropy is the
degree
or measure of
disorder
/ randomness (S)
solid is more
ordered
than liquids. liquids are more ordered than gases - GASSES ARE THE MOST
DISSORDERED
H20(s) = 48 JK-1 mol-1
H20(l) = 70 JK-1 mol-1
H20(g) = 189 JK mol-1
the HIGHER the
entropy
value = the HIGHER
degree
of disorder of a substance
crystalline solid = highly
ordered
arrangement;
low
entropy
melts becoming less ordered = entropy
increases
ordered metallic and ionic lattice =
Low
ENTROPY
melting point (s to l) there is a large increase in
disorder
boiling point (l to g) there is a
very
large increase in
disorder
as the atoms are more
far
apart from each other
the higher the
mr
value of the substance in the
SAME
state = the higher the
entropy
value
H2 (g) = 131 Jkmol CO2 (g) = 214 JKmol
mr= 2 mr= 44
entropy change = sum of entropy values of
products
- sum of entropy values of
reactants
determining entropy:
how much DISORDER there is aka the
state
DISSOLUTION
= if the solid is able to dissolve it increases its disorder so entropy
increases
AMOUNT
OF PARTICLES = more
particles
mean more entropy as there are more ways their
energy
can be arranged
free energy change (ΔG) is a measure used to
predict
whether a reaction is
feasible
feasible reaction is one that once started will carry on to
completion
without any
energy
being supplied to it
feasibility of a reaction depends on:
enthalpy
change of a reaction
entropy
change of a reaction
temperature
at which reaction is occurring
If free energy change (ΔG) is
0
or
negative
= reaction is
FEASIBLE
free energy change [ΔG] =
enthalpy
change [ΔH] – (
temperature
x
entropy
change [ΔS])
units for: ∆G = ∆H - T∆S
ΔG =
J
mol-1
ΔH = J
mol-1
T =
K
ΔS =
J
K-1
mol-1
ensure units are consistent so to convert KJ into J we
x1000
when working out minimum temperature for a reaction to become feasible you must convert ∆G = ∆H - T∆S
T
= ∆
H
/ ∆
S
we assume ∆G is
0
for a reaction to be feasible (
temp
x
entropy
change) part of the equation must be BIGGER than (
enthalpy
change)
free-energy graphs: ∆G vs T
the graph is a straight line so can use y = mx + c rearranged
gradient (
m
) = -entropy change {-∆S}
y - intercept (c) = enthalpy change {∆H}
equation
∆ G = (-∆
S
x
T
) + ∆
H