Firstly, the EXCITATION of the neurone cell, TRIGGERED BY A STIMULUS, causes the SODIUM ION CHANNELS to OPEN , as a result of making it more PERMEABLE to sodium ions
the sodium ions now diffuse into the the axon down the electrochemical gradient, thus makes the inside LESS NEGATIVE
2. What happens upon reaching the threshold of -55mV?
Even more sodium ion channels open, eventually giving a potential difference of +40mV.
This is the END OF DEPOLARISATION. Now repolarisation starts
3. How is repolarisation achieved?
As a result of sodium ion channels CLOSING and potassium ion channels OPENING.
The K+ions diffuse out of the neurone down the conc gradient and eventually RESTORE THE RESTING POTENTIAL.
However, as the closing of the k+ion channels is slightly delayed, this leads to HYPERPOLARISATION
What is hyperpolarisation?
When the potential difference becomes more negative than the resting potential
Hyperpolarisation- how is the resting potential then achieved?
With help of sodium-potassium pump which returns the potential difference to -70mV