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Paper 1
Algebra
Rearranging formulae
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Connor McKeown
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Cards (33)
What is a formula?
A
formula
is a
mathematical
relationship consisting of
variables
,
constants
, and an
equals
sign.
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What are some examples of formulae you will encounter in the IGCSE course?
Examples include formulae for
areas
and
volumes
of
shapes
, equations of
lines
and
curves
, and the relationship between
speed
,
distance
, and
time.
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What is the equation of a straight
line
?
The equation of a straight line is given by
y
=
y =
y
=
m
x
+
mx +
m
x
+
c
c
c
.
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What is the formula for the area of a trapezium?
The area of a
trapezium
is given by
A
r
e
a
=
Area =
A
re
a
=
(
a
+
b
)
h
2
\frac{(a + b)h}{2}
2
(
a
+
b
)
h
.
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What is Pythagoras' theorem?
Pythagoras' theorem states that
a
2
+
a^2 +
a
2
+
b
2
=
b^2 =
b
2
=
c
2
c^2
c
2
.
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What does rearranging formulae mean?
Rearranging formulae
means
changing
the subject of the formula to
isolate
a specific
variable.
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What is the first step in rearranging formulae?
The
first
step is to
remove
any
fractions
or
brackets.
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How do you remove fractions when rearranging a formula?
You remove fractions by
multiplying both sides
by anything on the
denominator.
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What should you do if expanding brackets does not help in rearranging a formula?
If expanding brackets does not help, it may be easier to
leave
the
bracket
as is.
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What is the method for isolating a variable in a rearranged formula?
You carry out
inverse
operations to
isolate
the
variable
you are trying to make the
subject.
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How do you rearrange the formula
A
=
A =
A
=
(
a
+
b
)
h
2
\frac{(a + b)h}{2}
2
(
a
+
b
)
h
to make
h
h
h
the subject?
Multiply by 2
to get
2
A
=
2A =
2
A
=
(
a
+
b
)
h
(a + b)h
(
a
+
b
)
h
and then
divide
by
(
a
+
b
)
(a + b)
(
a
+
b
)
to
isolate
h
h
h
.
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How do you make
x
x
x
the subject of the formula
y
=
y =
y
=
a
x
5
ax^5
a
x
5
?
First, divide both sides by
a
a
a
to get
y
a
=
\frac{y}{a} =
a
y
=
x
5
x^5
x
5
, then take the
5th
root of both sides.
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What happens if
n
n
n
is even when rearranging a formula?
If
n
n
n
is even, there will be two answers:
a positive and a negative.
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How do you reverse an nth root
in
a formula?
You reverse an nth root by
raising both sides
to the
power
of
n
n
n
.
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What are some common formulae for accelerating objects?
Common formulae include
v
=
v =
v
=
u
+
u +
u
+
a
t
at
a
t
,
v
2
=
v^2 =
v
2
=
u
2
+
u^2 +
u
2
+
2
a
s
2as
2
a
s
, and
s
=
s =
s
=
u
t
+
ut +
u
t
+
1
2
a
t
2
\frac{1}{2}at^2
2
1
a
t
2
.
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What does the letter
t
t
t
represent in the formulae for accelerating objects?
t
t
t
stands for the
amount
of
time
something
accelerates
for (in
seconds
).
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What does the letter
u
u
u
represent in the formulae for accelerating objects?
u
u
u
stands for the
initial speed
(in m/s) - the speed at the
beginning.
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What does the letter
v
v
v
represent in the formulae for accelerating objects?
v
v
v
stands for the
final speed
(in
m/s
) - the speed after
t
t
t
seconds.
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What does the letter
a
a
a
represent in the
formulae
for accelerating objects?
a
a
a
stands for
acceleration
(in
m/s²
) during that time.
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What does the letter
s
s
s
represent
in the formulae for accelerating objects?
s
s
s
stands for the
distance
covered in
t
t
t
seconds.
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Do you need to memorize the common formulae for accelerating objects?
No
,
you do not need to memorize these formulae
, but
you should know how to rearrange them.
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What is the difference between initial speed
(
u
)
(u)
(
u
)
and final speed
(
v
)
(v)
(
v
)
?
The initial speed
(
u
)
(u)
(
u
)
is the speed at the
beginning
, while the final speed
(
v
)
(v)
(
v
)
is the speed
after
t
t
t
seconds.
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What is the first step to rearranging the formula
y
=
y =
y
=
a
x
2
−
b
c
\frac{ax^2 - b}{c}
c
a
x
2
−
b
to make
x
x
x
the subject?
The
first
step is to
square
both sides.
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What should you do after squaring both sides in the rearrangement process?
You should
add
b
b
b
to both sides.
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What is the final step to isolate
x
x
x
in the rearrangement process?
The
final
step is to square
root
both sides.
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What should you do if the subject appears twice in a formula?
You will need to
factorise
at some
point.
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How do you rearrange a formula where the subject appears inside a set of brackets?
You will need to
expand
these
brackets
before you can begin
rearranging.
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What should you do if the subject appears on two sides of a formula?
You will need to
bring
those
terms
to the
same side
before you can
factorise.
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How do you rearrange the formula
p
=
p =
p
=
2
−
a
x
x
−
b
\frac{2 - ax}{x - b}
x
−
b
2
−
a
x
to make
x
x
x
the subject?
Get rid of
the
fraction by multiplying both sides by
the
expression on the
denominator.
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What is the next step after multiplying both sides by the denominator in the formula
p
=
p =
p
=
2
−
a
x
x
−
b
\frac{2 - ax}{x - b}
x
−
b
2
−
a
x
?
Expand
the
brackets
on the
left-hand side
to
'release'
the
variable.
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What should you do after expanding the brackets in the rearrangement process?
Bring
the terms containing
x
x
x
to one side of the
equals
sign and any other terms to the
other
side.
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How do you factorise the left-hand side of the equation to isolate
x
x
x
?
Factorise
the left-hand side to bring
x
x
x
outside
of the brackets, so that it appears only
once.
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What is the final step to isolate
x
x
x
in the formula
p
=
p =
p
=
2
−
a
x
x
−
b
\frac{2 - ax}{x - b}
x
−
b
2
−
a
x
?
Isolate
x
x
x
by
dividing
by the
whole expression.
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