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Paper 1
Algebra
Algebraic roots & indices
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Created by
Connor McKeown
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Cards (15)
What is the topic of the study material?
Algebraic
Roots &
Indices
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Can the laws of indices be used with algebraic terms?
Yes
, the laws of indices work with
numerical
and
algebraic
terms.
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How can you simplify expressions where terms are multiplied or divided?
By dealing with the
number
and
algebraic parts
separately.
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What is the result of simplifying
3
x
7
×
6
x
4
3x^7 \times 6x^4
3
x
7
×
6
x
4
?
The result is
18
x
11
18x^{11}
18
x
11
.
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What does
3
x
7
÷
6
x
4
3x^7 \div 6x^4
3
x
7
÷
6
x
4
simplify to?
It
simplifies
to
1
2
x
3
\frac{1}{2}x^3
2
1
x
3
.
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What is the result of
(
3
x
7
)
2
(3x^7)^2
(
3
x
7
)
2
?
The result is
9
x
14
9x^{14}
9
x
14
.
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How can you solve equations when the unknown is in the index?
If
two
powers are
equal
and the
base
numbers are the
same
, then the indices must be the
same.
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What is the implication of the equation
a
x
=
a^x =
a
x
=
a
y
a^y
a
y
?
It implies that
x
=
x =
x
=
y
y
y
.
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What should you do if the unknown is part of the index?
You should write
both
sides with the same
base
number.
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How do you solve the equation
5
2
x
=
5^{2x} =
5
2
x
=
125
125
125
?
Rewrite it as
5
2
x
=
5^{2x} =
5
2
x
=
5
3
5^3
5
3
to find
2
x
=
2x =
2
x
=
3
3
3
, thus
x
=
x =
x
=
3
2
\frac{3}{2}
2
3
.
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How do you solve
8
x
=
8^x =
8
x
=
1
/
4
1/4
1/4
?
You
rewrite
it as
4
−
1
=
4^{-1} =
4
−
1
=
2
−
2
2^{-2}
2
−
2
to find
8
x
=
8^x =
8
x
=
2
−
2
2^{-2}
2
−
2
.
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What is the process
to
solve
2
3
x
=
2^{3x} =
2
3
x
=
2
−
2
2^{-2}
2
−
2
?
Set
the
indices equal
to
each other
:
3
x
=
3x =
3
x
=
−
2
-2
−
2
, thus
x
=
x =
x
=
−
2
3
-\frac{2}{3}
−
3
2
.
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What are the steps to simplify <latex>(3x^2)(2x^3y^2)/(6x^2y)
Multiply
out the
brackets
in the
numerator.
Rearrange
the numerator to
multiply numbers
,
terms
, and
variables
together.
Simplify
the
numerator.
Multiply constants
and add
powers
of the terms.
Divide
the
constants.
Subtract
the
power
of the
term
in the denominator from the
numerator.
Simplify
the
expression.
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What are the steps to simplify <latex>\frac{54x^7}{2x^4} - \frac{1}{3}
Simplify the expression
inside
the brackets.
Cancel down the
constants.
Subtract the
power
of the term in the denominator from the numerator.
Apply the
negative
index outside the brackets by flipping the fraction.
Apply the
fractional
index outside the brackets to everything inside the brackets.
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Where can students find more resources for algebraic roots and indices?
Students
can visit
www.savemyexams.com
for
more resources.
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