topic 3 heat

Cards (27)

  • q=q=mcΔtmcΔt
    where
    q = energy
    m = mass
    c = specific heat capacity
    Δt = change in time
  • q=q=mLmL
    where
    q = energy
    m = mass
    L = latent heat capacity
  • phases changes use potential energy, the energy between molecular bonds, while heat changes are kinetic energy, given by heat or speed changes of the molecules
  • in a solid, molecules can only vibrate, not translate
  • in a liquid, molecules can vibrate and move freely in a fixed volume
  • in going from a solid to liquid, some intermolecular bonds are broken and allow the molecules freedom for motion
  • in going from a liquid to a gas, most of the intermolecular bonds are broken
  • sublimation is going from a solid to a gas. deposition is going from a gas to solid
  • Eint=E_{int}=Ek+E_k+EpE_p
    where
    internal energy = kinetic energy + potential energy
  • the thermometer measures kinetic energy; thus when a substance is going through a phase change, the temperature will not change. The energy that is being transformed when adding heat is the potential energy between the intermolecular bonds being broken.
  • the celcius degree at which every gas attains a pressure of 0 is at -273 degrees celcius
  • kelvin: the SI base unit of thermodynamic temperature (equivalent in size to the degree Celsius). its 0 starts at celcius's -273
  • one kilocalorie is the amount of heat needed to raise one kilogram of water by 1 degree celcius
  • 1 kcal = 4.186kJ
  • for food, calories are really a kilocalorie (kcal)
  • 473Cal=473 Cal=473Cal473Cal*(4.186kJ)/(1Cal)=(4.186kJ)/(1Cal) =1143kJ 1143kJ
    example: if a snickers bar is 473 calories, how many joules is it?
  • p=p=m/vm/v
    pressure = mass/volume
  • example: air has a density of about p=1.2kgm^-3.
    How much het, in joules, is needed to raise the temperature of the air in a 3m by 4m by 5m room by 5 degrees celcius?
    *air's specific heat capacity is =1050
    solution:
    formula: mcΔT
    c=1050
    ΔT=5

    step 1:
    find m
    p=m/v
    (1.2)=m/(3*4*5)
    1.2*60=m
    m= 72

    thus,
    (72)*(1050)*5= heat needed
    heat needed is 37000J
  • (ideal gas) p=F/A
    where
    p= pressure
    F= force
    A= area

    p here describes the pressure that the walls of the box feel exerted by the molecule within it (newton's third law, molecule exerts an equal and opposite force on the walls of the box)

    units:Nm^-2, Pascals (Pa)
  • n=n=N/NaN/N_a
    where
    n= number of moles
    N= number of atoms
    N_a= Avogadro's constant
  • ideal gas law
    pV=pV=nRTnRT
    where
    p=pressure
    v=volume
    n= number of moles
    R= gas constant
    T= temperature
  • average kinetic energy per molecule of gas
    Ek=E_k=(3/2)kbT(3/2)k_bT
    or Ek=E_k=(3/2)(R/N)T(3/2)(R/N)T
    where
    K_b= boltzmann's constant
    R= gas constant
    N= number of atoms
  • an ideal gas is an imaginary gas that is used to model real gases
    • are identical perfect spheres
    • are perfectly elastic, dont lose any kinetic energy during collisions with each other or the walls of their container
    • have no intermolecular forces - potential energy does not change when heated
    • are so small that their volume is much smaller than the volume of their container
  • kinetic model of an ideal gas:
    • if temperature of gas increases, so does average speed (and hence kinetic energy) of the molecules
    • higher speed and temperature means more collisions with container walls. thus: higher pressure
  • avagadro's number
    6.02*10^23
    *1 mol = 6.02*10^3 of something
  • atomic weight is the highlighted number in a square in the periodic table
  • find
    1. the gram atomic weight of water
    2. the mass in grams of 1 mole of water
    3. how many moles of hydrogen and oxygen there are in 1 mole of water

    GAW of water (H_2O) is given by 2*(1.00794)+1(15.9994) = 18.01528g per mole.
    thus that is the mass of 1 mole of water
    since each mole of H2O has 2H and 1O, there are 2 moles of H and 1 mole of O for each mole of water