Cards (54)

    • What is the Quotient Rule used for?
      Differentiating quotients of functions
    • The Quotient Rule formula is \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>, where y=y =u(x)v(x) \frac{u(x)}{v(x)} and dydx\frac{dy}{dx} is the derivative
    • The Quotient Rule involves subtracting the product of the numerator's derivative and the denominator from the product of the numerator and the denominator's derivative.
    • Steps to apply the Quotient Rule
      1️⃣ Identify u(x)u(x) and v(x)v(x)
      2️⃣ Compute u(x)u'(x) and v(x)v'(x)
      3️⃣ Substitute into the Quotient Rule formula
      4️⃣ Simplify the result
    • What is the formula for the Quotient Rule?
      dydx=\frac{dy}{dx} =u(x)v(x)u(x)v(x)[v(x)]2 \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}
    • The Quotient Rule is used to differentiate functions that are the quotient of two other functions.
    • What is the formula for the Sum/Difference Rule?
      ddx[u(x)±v(x)]=\frac{d}{dx}[u(x) \pm v(x)] =u(x)±v(x) u'(x) \pm v'(x)
    • Match each differentiation rule with its formula:
      Sum/Difference Rule ↔️ ddx[u(x)±v(x)]=\frac{d}{dx}[u(x) \pm v(x)] =u(x)±v(x) u'(x) \pm v'(x)
      Product Rule ↔️ ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x)
    • What is the formula for the Quotient Rule?
      \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>
    • The Quotient Rule is used to differentiate functions that are the quotient of two other functions.
    • What is the formula for the Product Rule?
      ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x)
    • The Quotient Rule formula includes subtracting the product of the numerator's derivative and the denominator from the product of the numerator and the denominator's derivative.
    • What is the Quotient Rule formula?
      \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>
    • Match each differentiation rule with its formula:
      Sum/Difference Rule ↔️ ddx[u(x)±v(x)]=\frac{d}{dx}[u(x) \pm v(x)] =u(x)±v(x) u'(x) \pm v'(x)
      Product Rule ↔️ ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x)
      Quotient Rule ↔️ ddx[u(x)v(x)]=\frac{d}{dx}\left[\frac{u(x)}{v(x)}\right] =u(x)v(x)u(x)v(x)[v(x)]2 \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}
    • What is the general formula for the Quotient Rule when y=y =u(x)v(x) \frac{u(x)}{v(x)}?

      dydx=\frac{dy}{dx} =u(x)v(x)u(x)v(x)[v(x)]2 \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}
    • For the function y = \frac{x^{2}}{x + 1}</latex>, the derivative using the Quotient Rule is \frac{x^{2} + 2x}{(x + 1)^{2}}.
    • What is the Quotient Rule used to differentiate?
      The quotient of two functions
    • The Quotient Rule states that if y=y =u(x)v(x) \frac{u(x)}{v(x)}, then \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>, where dydx\frac{dy}{dx} is the derivative
    • For the function y=y =x2x+1 \frac{x^{2}}{x + 1}, the derivative using the Quotient Rule is \frac{x^{2} + 2x}{(x + 1)^{2}}.
    • What type of functions is the Quotient Rule used to differentiate?
      Fractions of functions
    • For y = \frac{x^{2}}{x + 1}</latex>, the derivative dydx\frac{dy}{dx} is \frac{x^{2} + 2x}{(x + 1)^{2}}
    • The Quotient Rule formula is dydx=\frac{dy}{dx} = \frac{u'(x)v(x) + u(x)v'(x)}{[v(x)]^{2}}.

      False
    • What is the formula for differentiating a sum of functions using the Sum/Difference Rule?
      \frac{d}{dx}[u(x) \pm v(x)] = u'(x) \pm v'(x)</latex>
    • The Product Rule states that ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x). An example of its application is 2x \sin x + x^{2} \cos x
    • Match the differentiation rule with its formula:
      Sum/Difference Rule ↔️ ddx[u(x)±v(x)]=\frac{d}{dx}[u(x) \pm v(x)] =u(x)±v(x) u'(x) \pm v'(x)
      Product Rule ↔️ ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x)
      Quotient Rule ↔️ u(x)v(x)u(x)v(x)[v(x)]2\frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}
    • What is an example of a derivative calculated using the Quotient Rule?
      \frac{2x(x + 1) - x^{2}}{(x + 1)^{2}}</latex>
    • For y=y =x2x+1 \frac{x^{2}}{x + 1}, the derivative dydx\frac{dy}{dx} using the Quotient Rule is \frac{x^{2} + 2x}{(x + 1)^{2}}
    • The Quotient Rule is used to differentiate functions of the form y = \frac{u(x)}{v(x)}
    • What is the formula for the Quotient Rule?
      \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>
    • What is the derivative of 2x+2x +3 3 using the Sum/Difference Rule?

      22
    • The Product Rule states that ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x), where u(x)u'(x) is the derivative of u(x)
    • Give an example where the Quotient Rule is used to find the derivative of \frac{x^{2}}{x + 1}</latex>
      \frac{x^{2} + 2x}{(x + 1)^{2}}
    • The Quotient Rule is used to differentiate functions that are the sum of two other functions.
      False
    • The Quotient Rule is used to differentiate functions that are the quotient of two other functions.
    • What does u(x)u'(x) represent in the Quotient Rule?

      Derivative of the numerator
    • Steps to apply the Quotient Rule:
      1️⃣ Identify u(x)u(x) and v(x)v(x).
      2️⃣ Compute u(x)u'(x) and v(x)v'(x).
      3️⃣ Use the formula: ddx(uv)=\frac{d}{dx}\left(\frac{u}{v}\right) =uvuvv2 \frac{u'v - uv'}{v^{2}}.
      4️⃣ Simplify the resulting expression.
    • The derivative of v(x)=v(x) =x+ x +1 1 is v(x)=v'(x) =2 2.

      False
    • The Quotient Rule states that if y=y =u(x)v(x) \frac{u(x)}{v(x)}, then \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>, where v(x)v'(x) is the derivative of the denominator
    • What is the derivative of the denominator in the Quotient Rule called?
      v(x)v'(x)
    • To apply the Quotient Rule, we use the formula \frac{d}{dx}\left(\frac{u}{v}\right) = \frac{u'v - uv'}{v^{2}}
    See similar decks