Identidades trigonometricas

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Created by
Melanie

Cards (15)

  • sen2x=sen^{2}x=

    1−cos2(x)1-cos^{2}(x)
  • cos2(x)=cos^{2}(x)=

    1−sen2(x)1-sen^{2}(x)
  • sen2x=sen^{2}x=

    ==1−cos2(x)2\frac {1-cos2(x)}{2}
  • cos2x=cos^{2}x=

    ==1+cos2(x)2\frac {1+cos2(x)}{2}
  • sec2(x)=sec^{2}(x)=

    ==1+1+tan2(x)tan^{2}(x)
  • csc2(x)=csc^{2}(x)=

    1+1+cot2(x)cot^{2}(x)
  • sen(2x)=sen(2x)=

    2sen(x)cos(x)2sen(x)cos(x)
  • cos(mx)cos(nx)=cos(mx)cos(nx)=

    ==12cos(m−n)x+\frac {1}{2}cos(m-n)x+12cos(m+n)x\frac {1}{2}cos(m+n)x
  • sin(mx)⋅sin(nx)=sin(mx)\cdot sin(nx)=

    12cos(m+n)x−12cos(m−n)x\frac {1}{2}cos(m+n)x-\frac{1}{2}cos(m-n)x
  • sin(x+y)=sin(x+y)=

    ==sin(x)cos(y)+sin(x)cos(y)+cos(x)sin(y)cos(x)sin(y)
  • cos(x+y)=cos(x+y)=

    cos(x)cos(y)−sin(x)sin(y)cos(x)cos(y)-sin(x)sin(y)
  • sin(x)cos(x)sin(x)cos(x)

    ==12sin(2x) \frac {1}{2}sin(2x)
  • sin(x)cos(y)=sin(x)cos(y)=

    12(sin(x−y)+\frac {1}{2}(sin(x-y)+sin(x+y))sin(x+y))
  • cos(2x)=cos(2x)=

    ==2cos2(x)−12cos^2(x)-1
  • sin(x)+sin(x)+sin(y)=sin(y)=

    (2)⋅sinx+y2⋅cosx−y2(2) \cdot sin\frac{x+y}{2} \cdot cos\frac{x-y}{2}