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Organic Functional Groups
Equations, Electrochem, and Polymers
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Cards (46)
E=hv
E=energy
h=Planck's Constant (6.63 x 10^-34 J/hertz
v=frequency
Faraday's Constant
9.65*10^4 C*mol^-1
A=3cl
A=absolute absorbance
3(actually flipped)=molar absorbance coefficent
c=concentration
l=pathlength
%T=
I
t
/
I
0
∗
I_t/I_0*
I
t
/
I
0
∗
100
100
100
%T=percent transmittance
I(t)=intensity of transmitted light
I(0)=transmitted light through reference
Note: %T is proportional to absorbance NOT concentration
Wavelength=
c
/
v
c/v
c
/
v
c=speed of light (3.0*10^8)
v=frequency
E=
E
0
(
c
a
t
h
o
d
e
)
−
E
0
(
a
n
o
d
e
)
E_0(cathode) - E_0(anode)
E
0
(
c
a
t
h
o
d
e
)
−
E
0
(
an
o
d
e
)
E=reduction potential of galvanic cell
E(c)=reduction potential of the cathode
E(a)=reduction potential of the anode
e=F/L
Calculating the charge of 1 election
e=electron charge
F=Faraday's Constant
L=Avogadro's Number
E=
E
0
−
R
T
/
n
F
(
l
n
[
O
x
]
/
[
R
e
d
]
)
E_0-RT/nF(ln[Ox]/[Red])
E
0
−
RT
/
n
F
(
l
n
[
O
x
]
/
[
R
e
d
])
E=reduction potential of cell
E_0=standard reduction potential
R=gas constant 8.314 J/mol
n=moles/number of electrons
F=Faraday's Constant (9.65*10^4 C*mol^-1)
[Ox] = Concentration of Anode or species being oxidized
[Red] = Concentration of Cathode or species being reduced
delta G =
−
n
F
E
0
-nFE^0
−
n
F
E
0
delta G=standard free energy change
n=number/moles of electrons
F=Faraday's Constant (9.65*10^4 C*mol^-1)
E^0=standard reduction potential
NoteL The more positive the cell potential=the greater tendency for the reaction to proceed to the right
v- =
1
/
2
p
i
c
(
s
q
r
t
(
k
/
m
)
1/2pi c (sqrt(k/m)
1/2
p
i
c
(
s
q
r
t
(
k
/
m
)
v- = stretching frequency
c=speed of light (3.0 *10^8 m/s)
k=force constant
m=mass average
E=
E
0
−
0.0592
/
n
(
l
o
g
[
O
x
]
/
[
R
e
d
]
)
E_0-0.0592/n(log[Ox]/[Red])
E
0
−
0.0592/
n
(
l
o
g
[
O
x
]
/
[
R
e
d
])
E=reduction potential
E_0=standard reduction potential
n=number of electrons
[Ox] = concentration of anode or oxidative species
[Red]=concentration of cathode or reductive species
Number Average Molar Mass Mn=
s
u
m
N
i
M
i
/
s
u
m
N
i
sumNiMi/sumNi
s
u
m
N
i
M
i
/
s
u
m
N
i
Ni=number of chains/moles with molar mass Mi
Mi = molar mass
Mass Average Molar Mass Mw =
s
u
m
N
i
M
i
2
/
N
i
M
i
sumNiMi^2/NiMi
s
u
m
N
i
M
i
2
/
N
i
M
i
Mw=Mass average molar mass
Ni=number of chains/moles at molar mass Mi
Mi=molar mass
Heterogeneity Index:
M
w
/
M
n
M_w/M_n
M
w
/
M
n
Mw= mass average
Mn=number average molar mass
I=
V
/
R
V/R
V
/
R
I=Current (Amps)
V=Voltage (V)
R=Resistance
Don't forget about H in between methyl groups
What orbitals are involved in a C-C bond?
s
p
3
sp^3
s
p
3
What orbitals are involved in C double bonded to C?
p and sp^2
What orbitals are involved in C triple bond to C?
2p and sp
The more positive the reduction potential, the more powerful the oxidant
i_p=
k
C
0
s
q
r
t
(
v
)
kC_0sqrt(v)
k
C
0
s
q
r
t
(
v
)
i_p=peak current
k=simple constant including square root of diffusion coefficient
C0=concentration of bulk solution (mol/cm^3)
v=scan rate
Planck’s Constant
6.63 x 10^-34
The more positive the oxidant, the weaker the reductant species
The more positive the reduction potential, the more powerful the oxidant
(
C
+
1
)
+
(C+1) +
(
C
+
1
)
+
(
N
/
2
)
−
(
H
/
2
)
(N/2) - (H/2)
(
N
/2
)
−
(
H
/2
)
Double Bond Equivalence
C= # of carbon atoms
N = # of nitrogen atoms
H = # of hydrogen atoms OR # of halogen atoms
Nuclei with both p and n even (Charge and mass are even) have a spin of 0
Nuclei with p and n odd have integral spin (Charge is odd but mass is even). Calculated by charge (oxidation number) minus mass
Nuclei with odd mass have half integral spin
The peak current increases linearly as a function of the squareroot of v.
A=
l
o
g
(
I
0
/
I
t
)
log(I_0/I_t)
l
o
g
(
I
0
/
I
t
)
I_0= Intensity of light passed through reference
I_t= Intensity of light passed
1
0
A
=
10^A=
1
0
A
=
(
I
0
/
I
t
)
(I_0/I_t)
(
I
0
/
I
t
)
=
=
=
I
0
/
(
I
0
−
I
a
)
I_0/(I_0-I_a)
I
0
/
(
I
0
−
I
a
)
A= absolute absorbance (unitless)
I_0= Intensity of light through reference
I_t= Intensity of light transmitted
I_a =Intensity of light absorbed
delta E= yh/B0
E= Energy of NMR spectrum
y= Magnoyro Ration (y) = 2.68 x 10^8 s^-1 T^-1
h = Reduced Planck's Constant (1.05 x 10^-34 J*s)
B0=Boltzmann Constant (1.38 x 10^-23 J*K^-1)
Aromatic Proton (NMR Spectrum)
7-8
Vinyl Protons
5-6
Note: Vinyl Protons are directly attached to a C-C DOUBLE bond
Acetylenic Protons
2.5
Aldehyde Protons
9-10
Carboxylic Acid Protons
12
The peak current (Ipkc or Ipka) is
directly
related to the square root of scan rate (v)
Wavelength=c/v
c=speed of light
v=frequency
Note: because v- (stretching frequency) is reciprocal of wavelength,
v- = v/c
What IR band is a nitrile?
2250
cm^1
See all 46 cards
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