Boiling points reflect the strength of forces between molecules. The more they stick together, the more energy it will take to blast them into the atmosphere as gases.
There are 3 important trends to consider: 1) The relative strength of the four intermolecular forces, 2) Boiling points increase as the number of carbons is increased, 3) Branching decreases boiling point.
The longer the carbon chain, the higher the boiling point due to the increased Van der Waals attractive forces between molecules, and the lower the water solubility because the non-polar part is getting longer and hence a smaller proportion of the molecule is interacting in the water.
The more spherical (branched) the molecules, the less surface area it has, resulting in a lower boiling point than other isomeric alcohols due to less Van der Waals attractive forces between molecules, and more soluble in water because the non-polar surface area is minimized.
The extent of solubility of any alcohol in water depends on the capability of its molecule to form hydrogen bonds with water. But, within isomeric alcohols, solubility increases with branching due to the decrease in surface area of the non-polar hydrocarbon part.
pKa range: 15.5-18.0 (pKa water = 15.7)<|>Acidity decreases as alkyl group increases<|>Halogens increase the acidity (inductive effect)<|>Phenol (10.0) is 100 million times more acidic than cyclohexanol (18.0) (delocalization)
Phenols (pKa ~10) are much more acidic than alcohols (pKa ~ 16) due to resonance stabilization of the phenoxide ion<|>Phenols react with NaOH solutions (but alcohols do not), forming salts that are soluble in dilute aqueous solution
Reagent is mercury(II) acetate which dissociates slightly to form +Hg(OAc) in H2O, +Hg(OAc) is the electrophile, will be attacked by the pi bond, Sodium borohydride (NaBH4), a reducing agent, replaces the mercury with hydrogen
Borane, BH3, adds a hydrogen to the most substituted carbon in the double bond, The alkylborane is then oxidized to the alcohol which is the anti-Mark product
Hydride ion, H-, attacks the carbonyl carbon, forming an alkoxide ion, Then the alkoxide ion is protonated by dilute acid, Only reacts with carbonyl of aldehyde or ketone, not with carbonyls of esters or carboxylic acids