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Maths
pure
Y2 calculus
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Created by
Milan Savier
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Cards (7)
Differentiating rules
ln
(
x)
=
1
/
x
sinkx
=
kcoskx
coskx
=
-ksinkx
e^kx
=
ke^kx
a^kx
= a^kx * kln(a)
chain rule
dy/dx = dy/du * du/dx
e.g. y = (3x^4 + x)^
5
bring down the power of
5
-->
5(3x...
multiply by
inside
of brackets
differentiated
dy/dx =
5(3x^4
+ x)^
4(12x^3
+
1
)
differentials (in formula booklet)
tankx =
ksec^2(kx)
coseckx =
-kcosec(kx)cot(kx)
seckx =
ksec(kx)tan(kx)
cotkx =
-kcosec^2(kx)
integration rules (don't forget +c)
x^n =
x
^(
n+1
)/
n+1
e^x
= e^x
1/
x
=
ln
|x| (
modulus
)
cosx =
sin(x
)
sinx =
-cos
(x)
sec^2(x) =
tan
(x)
cosec(x)cot(x) =
-cosec
(x)
cosec^2(x) =
-cot
(x)
sec(x)tan(x) =
sec
(x)
integration by substitution
we are given an
expression
for u in terms of x
differentiate
(du/dx) to find an
expression
for dx in terms of du
use this expression to
rewrite
the
integral
in the du form
integrate this expression and
substitute
in x
product rule
for y =
uv
dy/dx =
uv'
+
vu'
quotient
rule
for y = u/
v
dy/dx = (
vu'-uv'
)/v^
2