Cards (62)

    • System
      Our interest
    • Surroundings
      The rest of the universe
    • Gibbs free energy
      Tells us if a change to our system will happen spontaneously or not
    • dG
      Change in free energy
    • ΔH
      Change in enthalpy
    • ΔS
      Change in entropy
    • T
      Temperature in Kelvin
    • Mass action ratio
      q = [C][D]/[A][B]
    • Mass action ratio
      • F-1,6-bP ⇌ G3P + DHP
    • ΔG⁰
      Standard Free Energy
    • R
      Gas constant
    • T
      Absolute temperature
    • q
      Mass action ratio
    • ΔG⁰ is the change in Free Energy when concentration of all reactants and products are 1M at 25°C, 1 atm.
    • ΔG⁰' is the Standard Free Energy at pH 7 at 25°C and 1 atm
    • ΔG depends on the nature of the reaction and the concentrations
    • If ΔG = 0
      No free energy change takes place, the system is at equilibrium
    • Rate up

      Rate down
    • Number of cars in
      Number of cars out
    • Rate of degradation

      Rate of formation of F-1,6-bP
    • The equilibrium constant is related to the standard free energy in a logarithmic manner
    • R=8.31x10^-3 kJ mol^-1 K^-1
    • Relationship between ΔG⁰' and Keq

      • ΔG⁰' = -5.7 kJ/mol, Keq = 10
      • ΔG⁰' = -11.5 kJ/mol, Keq = 100
      • ΔG⁰' = -17.3 kJ/mol, Keq = 1000
    • Relatively small changes in ΔG⁰' can lead to big changes in Keq
    • Conversion of dihydroxyacetone-phosphate to glyceraldehyde-3-phosphate

      [G3P]/[DHAP] = 0.0475 at equilibrium at 25°C
    • In vivo [DHAP] = 2 x 10^-4 M and [G3P] = 3 x 10^-6 M
    • ATP is the main energy carrier in the cell
    • Pi
      Inorganic phosphate
    • Adenylate Kinase interconverts ATP, ADP and AMP
      ATP + AMP ⇌ 2 ADP
    • In the body more energy is released as the reaction is not at equilibrium
    • A cheetah running 110 km/h uses 55g ATP/s
    • A cheetah weighs 20-70 kg
    • A 10 s sprint uses 0.55 kg ATP or 3% of body weight for a small cheetah
    • Humans apparently need about 70 kg ATP/day
    • Glucose + Pi ⇌ Glucose-6-phosphate + H2O

      ΔG⁰' = +14.0 kJ/mol, Keq = 3.5 x 10^-3
    • ATP + H2O ⇌ ADP + Pi

      ΔG⁰' = -30.5 kJ/mol
    • Glucose + ATP ⇌ Glucose-6-phosphate + ADP

      ΔG⁰' = -16.5 kJ/mol, Keq = 8.0 x 10^2
    • Coupling to ATP shifts the equilibrium 5 orders of magnitude
    • This only works because Pi is a shared intermediate
    See similar decks