Save
Physiology, Neurobiology and Metabolism
7 -
Save
Share
Learn
Content
Leaderboard
Learn
Created by
Georgie
Visit profile
Cards (62)
System
Our
interest
Surroundings
The
rest
of the universe
Gibbs free energy
Tells us if a change to our system will happen spontaneously or not
dG
Change
in free
energy
ΔH
Change in
enthalpy
ΔS
Change in
entropy
T
Temperature
in Kelvin
Mass action ratio
q = [
C
][
D
]/[A][B]
Mass action ratio
F-1,6-bP
⇌ G3P +
DHP
ΔG⁰
Standard
Free
Energy
R
Gas
constant
T
Absolute
temperature
q
Mass action ratio
ΔG⁰
is the change in Free Energy when concentration of all reactants and products are 1M at
25°C
, 1 atm.
ΔG⁰
' is the Standard Free Energy at pH 7 at
25°C
and 1 atm
ΔG depends on the nature of the
reaction
and the
concentrations
If
ΔG =
0
No
free energy change
takes place, the system is at
equilibrium
Rate
up
Rate
down
Number
of cars
in
Number of cars
out
Rate
of degradation
Rate of
formation
of
F-1
,6-bP
The
equilibrium constant
is related to the
standard free energy
in a logarithmic manner
R
=8.31x10^-3 kJ mol^
-1
K^-1
T
=
298 K
Relationship
between ΔG⁰' and Keq
ΔG⁰' = -5.7 kJ/mol, Keq =
10
ΔG⁰' =
-11.5
kJ/mol, Keq =
100
ΔG⁰' =
-17.3
kJ/mol, Keq =
1000
Relatively
small
changes in ΔG⁰' can lead to big changes in
Keq
Conversion
of dihydroxyacetone-phosphate to glyceraldehyde-3-phosphate
[G3P]/[DHAP] = 0.0475 at equilibrium at
25°C
In vivo [DHAP] =
2
x 10^
-4
M and [G3P] = 3 x 10^-6 M
ATP
is the main
energy
carrier in the cell
Pi
Inorganic
phosphate
Adenylate Kinase interconverts ATP,
ADP
and
AMP
ATP
+
AMP
⇌ 2 ADP
In the body more energy is released as the
reaction
is not at
equilibrium
A cheetah running
110
km/h uses
55g ATP/s
A cheetah weighs
20-70
kg
A
10
s sprint uses
0.55
kg ATP or 3% of body weight for a small cheetah
Humans apparently need about
70
kg ATP/day
Glucose
+ Pi ⇌ Glucose-6-phosphate + H2O
ΔG⁰' = +14.0 kJ/mol, Keq =
3.5
x 10^
-3
ATP +
H2O
⇌ ADP +
Pi
ΔG⁰'
=
-30.5
kJ/mol
Glucose
+ ATP ⇌ Glucose-6-phosphate + ADP
ΔG⁰' = -16.5 kJ/mol, Keq =
8.0
x
10
^2
Coupling to ATP shifts the equilibrium
5
orders of magnitude
This only works because
Pi
is a shared
intermediate
See all 62 cards