ap biology unit 6

Cards (72)

  • in the 1950s rosalind franklin preformed ____
    x ray crystallography of DNA
  • what did edwin chargaff find
    that the amount of adenine equals the amount of thymine, and the amount of cytosine equals the amount of guanine
  • purines

    double ring structure
  • pyrimidines
    single ring structure
    -“small structure big name”
  • adenine and thymine have __ hydrogen bonds

    2
  • cytosine and guanine have __ hydrogen bonds
    3
  • what did watson and crick do

    they combined the findings of franklin and chargaff to create the first 3d double helix model of DNA
  • dna is a
    double stranded helix
  • backbone of dna

    sugar phosphate
  • center of dna
    nucleotide pairing
  • dna strands are
    antiparallel
  • 5 prime end of dna

    free phosphate group
  • 3 prime end of dna
    free hydroxyl group
  • dna is the primary source of
    heritable information
  • eukaryotic cells
    dna is found in the nucleus
    linear chromosomes
  • prokaryotic cells

    dna is found in the nucleotide region
    chromosomes are circular
  • plasmids
    small circular dna molecules that are separate from the chromosomes
  • plasmids replicate ______ from the chromosomal dna
    independently
  • plasmids are primarily found in
    prokaryotes
  • when the ____ plasmid is inserted back into the bacteria the ___ will be _____
    recombinant, gene, expressed
  • bacteria can ______ ____ found on plasmids with neighbouring bacteria
    exchange genes
  • rna
    ribonucleic acid
    single stranded ribose sugar and phosphate backbone
  • dna
    deoxyribosenucleic acid
    double stranded deoxyribose sugar and phosphate backbone
  • 3 models for dna replication
    conservative, semi conservative, dispersive
  • conservative model
    the parental strands direct synthesis of: an entirely new double stranded molecule
  • semi conservative model

    the two parental strands each make a copy of itself
    -after one round of replication, the two daughter molecules each have one parental and one new strand
  • dispersive model

    the material in the two parental strands is dispersed randomly between the two daughter molecules
    -after one round of replication the daughter molecules contain a random mix of parental and new dna
  • meselson and stahls experiment

    1.bacteria was cultured with a heavy isotope 15N
    2.bacteria was transferred to a medium with 14N, a light isotope
    3.dna was centrifuged and analyzed after each replication
  • 1st step in dna replication

    dna replication begins at sites called origins of replication
    -various proteins attach to the origin of replication and open dna to form a replication fork
  • 2nd step in dna replication
    the enzyme helicase will unwind dna strands at each replication fork
    -ssbps (single strand bonding proteins) bind to the dna to keep it from reforming hydrogen bonds between nucleotide base pairs
    -topiosomerase will help prevent strain ahead of the replication fork by relaxing supercoiling
  • 3rd step in dna replication 

    the enzyme primase initiates replication by adding short segments of rna, called primers to the parental dna strand
    -enzymes that synthesize dna can only attach new dna nucleotides to an existing strand
    -primers serve as the foundation for dna synthesis
  • 4th step in dna replication 

    antiparallel elongation
    -dna polymerase 3 attaches to each primer on the parental strand and moves in the 3 to 5 prime direction
    -as it moves it adds nucleotides to the new strand in the 5 to 3 prime direction
    -the dnap 3 that follows helicase is known as the leading strand and it only requires 1 primer
    -the dnap 3 on the other parental strand that moves away from helicase is known as the lagging strand and it requires many primers
  • 5th step in dna replication

    the leading strand is synthesized in one continuous segment, but since the lagging strand moves away from the replication fork it is synthesized in chunks
  • 6th step in dna replication
    after dnap 3 forms an okazaki fragment, dnap 1 replaces rna nucleotides with dna nucleotides
  • okazaki fragments
    segments of the lagging strand
  • since dnap 3 can only add nucleotides to a 3 prime end, there is no way to finish _____ on the 5 prime end of a ______
    replication, lagging strand
  • over many replications this would mean that the dna would become ____
    shorter
  • telomeres
    repeating units of short nucleotide sequences that do not code for genes
    -form a cap at the end of dna to help postpone erosion
    -the enzyme telomerase adds telomeres to dna
  • as ______ adds nucleotides to the new dna strand, it proofreads the bases added
    dna polymerase
  • if errors still occur ____ will take place
    mismatch repair