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General Chemistry MCAT
Acid/Base Equilibria
Acid/ Base equilibria
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Cards (84)
Bronsted Lowry definition
Transfer of
protons
(proton is a
H+
)
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Bronsted Lowry (BL)
Acid
Proton donor
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Bronsted Lowry
(BL) Base
Proton acceptor
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Bronsted
Lowry
definition example
Water
and
HCl
Water
is BL base,
HCl
is BL Acid
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Lewis definition
Transfer
of
electron pairs
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Lewis acid
Electron pair
acceptor
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Lewis base
Electron pair
donor
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Lewis definition example
Water
and
BF3
Water is a
Lewis Base
, BF3 is a
Lewis acid
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BF3 as a Lewis acid
Boron
does not have octet (only
6
electrons), it is sp2 hybridized with an empty orbital that can accept an electron pair
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The H2O HCl reaction can only be explained by the
Lewis
definition, not the
Bronsted Lowry
definition
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H2O as a Lewis base
Electron pair donor
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H+ on HCl as a Lewis acid
Electron pair
acceptor
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Acid-base
equilibrium
H2O
+ HA ⇌
H30
+ + A-
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Water
Bronsted Lowry
base
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HA
Bronsted Lowry acid
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Hydronium
Conjugate
acid
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Conjugate base
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Ka
Acid dissociation
/
ionization
constant
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Pure solids
and
liquids
are not included in the equilibrium constant expression
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Strong acids
Donate
protons
very easily, making the
equilibrium
shift to the right towards products
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Conjugate base of a strong acid
Rather poor
at
accepting protons
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Large Ka
is a good way to recognize a strong
acid
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Weak acids
More likely to 'stay protonated', are less likely to
donate
their proton, equilibrium is to the left (towards the
reactants
)
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Small Ka
is a good way to recognize a
weak acid
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Water
Amphotetic, can act as both an
acid
or as a
base
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Autoionization of water
One
water
molecule acts as a base, the other as an acid, producing
H3O+
and OH-
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At
25°C
, Kw = 1.0 x
10-14
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Equilibrium in
autoionization
of water lies far to the
left
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Neutral
solution
[
H3O+
] = [
OH-
]
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Acidic
solution
[
H3O+
] > [
OH-
]
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Basic solution
[
H3O+
] < [
OH-
]
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pH of water at
25°C
is
7.00
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pH scale
pH
= 7 is neutral,
pH
< 7 is acidic, pH > 7 is basic
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Calculating hydronium ion concentration from pH
10-pH
=
[H3O+]
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pOH of water at
25°C
is
7.00
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pH
+
pOH
= 14
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Calculating pH of aqueous ammonia solution
[H3O+][OH-] =
1.0
x
10-14
pH =
14
-
pOH
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If first number is not
1.0
in [H3O+], subtract
0.5
from the exponent to estimate pH
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Strong
acids
Ionize 100
% in solution
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Calculating pH of 0.0030M HNO3 solution
pH =
-log
[H3O+] = -log(0.030M) =
1.52
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