Save
General Chemistry MCAT
Acid/Base Equilibria
Acid/ Base equilibria
Save
Share
Learn
Content
Leaderboard
Learn
Created by
Gabby Daniels
Visit profile
Cards (84)
Bronsted Lowry definition
Transfer of
protons
(proton is a
H+
)
Bronsted Lowry (BL)
Acid
Proton donor
Bronsted Lowry
(BL) Base
Proton acceptor
Bronsted
Lowry
definition example
Water
and
HCl
Water
is BL base,
HCl
is BL Acid
Lewis definition
Transfer
of
electron pairs
Lewis acid
Electron pair
acceptor
Lewis base
Electron pair
donor
Lewis definition example
Water
and
BF3
Water is a
Lewis Base
, BF3 is a
Lewis acid
BF3 as a Lewis acid
Boron
does not have octet (only
6
electrons), it is sp2 hybridized with an empty orbital that can accept an electron pair
The H2O HCl reaction can only be explained by the
Lewis
definition, not the
Bronsted Lowry
definition
H2O as a Lewis base
Electron pair donor
H+ on HCl as a Lewis acid
Electron pair
acceptor
Acid-base
equilibrium
H2O
+ HA ⇌
H30
+ + A-
Water
Bronsted Lowry
base
HA
Bronsted Lowry acid
Hydronium
Conjugate
acid
Conjugate base
Ka
Acid dissociation
/
ionization
constant
Pure solids
and
liquids
are not included in the equilibrium constant expression
Strong acids
Donate
protons
very easily, making the
equilibrium
shift to the right towards products
Conjugate base of a strong acid
Rather poor
at
accepting protons
Large Ka
is a good way to recognize a strong
acid
Weak acids
More likely to 'stay protonated', are less likely to
donate
their proton, equilibrium is to the left (towards the
reactants
)
Small Ka
is a good way to recognize a
weak acid
Water
Amphotetic, can act as both an
acid
or as a
base
Autoionization of water
One
water
molecule acts as a base, the other as an acid, producing
H3O+
and OH-
At
25°C
, Kw = 1.0 x
10-14
Equilibrium in
autoionization
of water lies far to the
left
Neutral
solution
[
H3O+
] = [
OH-
]
Acidic
solution
[
H3O+
] > [
OH-
]
Basic solution
[
H3O+
] < [
OH-
]
pH of water at
25°C
is
7.00
pH scale
pH
= 7 is neutral,
pH
< 7 is acidic, pH > 7 is basic
Calculating hydronium ion concentration from pH
10-pH
=
[H3O+]
pOH of water at
25°C
is
7.00
pH
+
pOH
= 14
Calculating pH of aqueous ammonia solution
[H3O+][OH-] =
1.0
x
10-14
pH =
14
-
pOH
If first number is not
1.0
in [H3O+], subtract
0.5
from the exponent to estimate pH
Strong
acids
Ionize 100
% in solution
Calculating pH of 0.0030M HNO3 solution
pH =
-log
[H3O+] = -log(0.030M) =
1.52
See all 84 cards