Acid, bases and buffers

    Cards (76)

    • Kw
      ionic product of water
    • Monobasic acid
      Acid that donates one mole of a proton
    • Brønsted-Lowry acid
      Species that donates a proton
    • monobasic acids
      HCl
      HCN
      HNO3
      CH3COOH
    • dibasic acid
      H2SO4
      H2CO3
    • tribasic acids
      H3PO4
      H3BO3
    • conjugate acid-base pair
      pair of two species that can be interconverted by a transfer of protons
      • A1 B2 —> A2 B1
      • acids have a positive charge
      • bases have a negative charge
    • larger Ka means more dissociation and a stronger acid
    • Ka
      acid dissociation constant
    • Ka of weak acids
      only paritally dissociate so theres more molecules of weak acid than of H+ and A-
    • Assumption of Ka of weak acids
      H+ = A-
      • HA dissociates to produce equal concentrations of the two
      • concentrant on of H+ due to the ionisation of water is negligible compared to the H+ concentration of the acid
    • Brønsted-Lowry base
      species that accepts a proton
    • Dibasic acid
      one mole of an acid can donate/release 2 protons
    • tribasic acid
      one mole of an acid can release/ donate 3 protons
    • acids dissociate and release H+ ions in aqueous solutions and alkalis dissociate and release OH- in aqueous solution
    • Calculating pH of strong Monobasic acids
      pH = -log[H+]
    • calculating the pH of strong bases
      Kw = [OH-][H+]
    • calculating the pH of weak acids 

      Ka= [H+]²/[HA]
    • Kw increases with increasing temperature as more bonds are broken (endothermic process)
    • assumptions for calculating pH of weak acids
      [HA] at the start is the same as [HA] in equilibrium
      • remains constant as dissociation is small
      this doesn’t apply when there’s a stronger weak acid
    • assumption for pH of weak acids do not always work
      -[H+] doesnt equal [A-] if the acid is very dilute
      -[HA] is not the same throughout if there’s a stronger weak acid
    • range of weak acids lies between pH 3 and 6
    • pH of strong monobasic acids
      complete dissociation in solution
      • [H+] = [HA]
      pH of strong acid can be calculated directly from the concentration of an acid
    • Kw
      if [H+(aq)] > [OH- (aq)] then the solution is acidic
    • Kw
      if [H+(aq)] < [OH- (aq)] then the solution is alkaline
    • pH of a buffer solution

      [H+] = Ka x [HA] / [A-]
    • what is a buffer solution?
      solution that minimises pH changes on the addition of small amounts of bases or acids
    • buffer
      [H+] / Ka = [HA] / [A-]
      • ratio of acid to its conjugate base
    • Kw
      if temperature increases, acid dissociates to a greater extent and so the Kw is higher
    • acid + base —> salt + water
    • acid + metal oxide —>salt + hydrogen (gas)
    • acid + alkali —> salt + water
    • How are buffers formed?
      weak acids and the salt of a weak acid
      • weak acid partially dissociates in solution and forms a relatively low concentration of A- ion
      • salt fully ionises in solution
      reserve supplies of acid and its conjugate base
    • formation of buffers example
      weak acid and salt of weak acid
      • ethanoic acid and sodium ethanoate
      • CH3COOH / CH3COONa
    • How are buffers formed?
      partial neutralisation of the weak acid
      • add aq alkali to excess weak acid
      • weak acid is partially neutralised by the alkali forming the conjugate base
      • some of the weak acid is left over unreacted so a mixture of salt and unreacted acid forms
    • buffer formation
      partial neutralisation e.g CH3COOH
      CH3COOH + NaOH —> CH3COONa + H2O
      CH3COOHCH3COO- + H+
    • action of a buffer
      Addition of an acid:
      • equilibrium shifts to the left
      • added H+ react with conjugate base
      • [H+] increases and pH is lowered
    • action of a buffer
      Addition of an alkali:
      • equilibrium shifts to the right (to replenish lost H+)
      • H+ (aq) + OH- (aq) —> H2O (l)
      • HA dissociates
      • [OH-] increases and pH increaases
    • buffer is most effective when there are equal concentrations of weak acid and its conjugate base
    • calculation of the pH of a buffer when its partial neutralisation
      n(acid used)
      n(alkali) = n(conjugate base formed)
      n(acid remaining) = n(acid used) - n(alkali added)