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Cards (80)
Mezzo
lineare
, omogeneo
isotropo
, e non
dispersivo
Esempio: il vuoto
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Permittività elettrica del vuoto
ε0 ≃
8.854·10−12
[
F/m]
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Permeabilità magnetica del vuoto
µ0 ≃
4π ·10−7
[
H/m
]
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Assenza di sorgenti
: ρ = 0, j = 0
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Campo
elettromagnetico
Solo funzione della
coordinata
z di un sistema
Cartesiano
e della coordinata
temporale
t
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Equazioni di Maxwell
1. ∇×e(z;t) = −µ0∂h(z;t)∂t
2. ∇×h(z;t) =
ε0∂e
(z;t)∂t
3. ∇·[
ε0e
(z;t)] =
0
4. ∇·[µ0h(z;t)] = 0
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ez(z;t)
costante
nello
spazio
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hz
(
z
;t)
costante
nello
spazio
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hz
(
z
;t)
costante nel tempo
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ez(z;t) costante
nel tempo
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ez = c1 =
0
, hz = c2 =
0
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Operatore dalambertiano
2
=
∂2∂z2
−
1c2∂2∂t2
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Velocità di fase
c = 1√µ0ε0 =
299792458
≃
2.998·108
(velocità della
luce
nel
vuoto
)
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ex(z,t)
=
f1(z-ct)
+
f2(z+ct)
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Onde piane nel dominio dei
fasori
Perdite
<|>
Velocità
di
fase
<|>
Velocità
di gruppo
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Onde piane
generiche
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ε0
Unità
di misura della
permittività elettrica
,
Fm−1
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µ0
Unità
di
misura
della
permeabilità magnetica
,
Hm−1
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[µ0ε0] =
s2 m−2
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c
Velocità
della
luce
nel
vuoto
,
ms−1
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c =
299792458
≃
2.998·108
ms−1
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Soluzione
dell'
equazione d'onda
ex
(
z
;t) =
f1
(z
-ct
) +
f2
(z
+ct
)
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f1(z
-ct
) e f2(z
+ct
) risolvono
l'equazione
di
d'Alembert
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Spostamento ∆z
∆z - c∆t =
0
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Velocità
di
fase
c =
∆z
/
∆t
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Impedenza caratteristica
ζ0 = √(µ0/ε0) ≃
377
Ω
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Onda piana armonica
ex = a cos(2π/λ (z -ct))
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ex
soddisfa l'equazione
di
d'Alembert
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λf
=
c
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ω =
2πc
/
λ
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Variazione
spaziale ∆(
2π
/
λ
z) = π/
2
∆z = λ/
4
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Velocità
di fase
vf
= c
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Polarizzazione lineare
Campo elettrico
e
campo magnetico giacciono sempre
nello stesso
piano
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ex = a
cos
(ωt -
2π
/
λ
z)
bx
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hy =
a
/
ζ0 cos
(
ωt
-
2π
/
λ z
)
by
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hy =
ex
/
ζ0
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Polarizzazione lineare
Campo elettrico
e
campo magnetico disegnano segmenti
nello
spazio
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z
Componente del
campo magnetico
nello
spazio
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x
Componente del
campo magnetico
nello
spazio
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y
Componente del
campo magnetico
nello
spazio
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See all 80 cards
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