A symptom of sickle cell anemia is respiratory failure
Sickle cell anemia is caused by low levels of O2
Electrophoresis showed that HbS has 2-3fewer negative charges in comparison to HbA
Ingram divided the HbA and HbS beta chains into multiple fragments instead of trying to sequence the whole thing
Sickle cell mutation at position 6 on the beta strand:
HbA is glutamic acid (Glu,E)
HbS is now valine (Val,V)
The hydrophobic βVal6 on the surface of HbS drives polymerization as a consequence of the hydrophobic effect
βVal6 from HbS tetramer 1 fits into a hydrophobicpocket on HbS tetramer 2, pocket formed by βPhe85 and βLeu88
By fluke of nature, each end of an HbS alpha/beta dimer interacts with another dimer, leading to long polymers
In HbS, the hydrophobic effect drives βVal6 to interact with βPhe85/βLeu88, leading to polymerization
In HbA, the interactions between βGlu6 and βPhe85/
βleu88 are NOT favourable for dimerization/polymerization to occur
High O2 concentration induces conformational change in hemoglobin, eliminating the hydrophobic binding pocket, therefore the mutated valine cannot interact with the pocket
Anfinsen's dogma / the thermodynamic hypothesis:
The native structure of a protein is determined by the protein's amino acid sequence (i.e. primary structure)
Almost all naturally occurring amino acids are “ alpha amino acids”, because the “amino” group is connected to the alpha carbon.
At pH values << 6, there is a high [H+] that favours the protonated state. If we titrate by adding OH-, we raise the pH and lower the [H+] so that we now favour the deprotonated or neutral form
-> The pKa is the pH at which the side chain is 50% protonated and 50% deprotonated
The pKa is a measure of the relative ease with which the side chain gives up its proton
His with a moderately low pKa (pKa≈6) deprotonates much more easily than Ser (pKa≈13.6). In other words, a higher pH, or a lower [H+] is required for Ser to deprotonate
The given pKa values are for side chains in aqueous solution
The pKa of HisA will be higher than in aqueous solution; The negatively charged Asp stabilizes the protonated form of HisA and shifts its pKa to a higher pH. The HisA holds on to its proton stronger than in aqueous solution
The pKa of HisB will be lower than in aqueous solution; The neutral Val stabilizes the neutral form of HisB and shifts its pKa to a lower pH value. In other words, HisB gives up its proton more easily than in aqueous solution
In Conformation A, His is close to a Val and will prefer to be deprotonated thus shifting the pKa lower (i.e. the His will likely be deprotonated at neutral pH=7)
In Conformation B, His is close to an Asp and will prefer to be protonated thus shifting the pKa higher (i.e. the His will likely be protonated at neutral pH=7)
We can intuitively estimate polarity from the structures of side chains. For example, the aliphatic chain of Isoleucine with four carbons (carbon is an atom with weak electro-negativity) is non polar; Serine with one carbon, but a polar hydrogen bonding OH group is
moderately polar, while the charged Aspartate is verypolar
Determining polarity: Isoleucine has a greater affinity for the organic phase, while Serine has moderate affinity for both the organic and the aqueous phase, and Aspartate has a greater affinity for the aqueous phase. By measuring the partition coefficients, we can establish a relative polarity scale
Side chain polarity dictates protein structure, which in turn dictates protein function;
Non-polar residues are found in the interior of globular proteins, and at the interfaces between different subunits
Hydrophobic residues (red) are clustered in the interior of a protein away from the aqueous environment. Polar hydrophilic residues (green) are typically found on the surface of the protein
A) what
Side chain polarity can also be used as a predictive tool
womp womp
A) H20
B) peptide bond
Properties of the peptide bond:
resonance leads to partial double bond character and restricted rotation
C=O and N-H groups are all coplanar
peptide bonds have a dipole moment;
peptide C=O is an H-bond acceptor (red arrow)
peptide N-H is an H-bond donor (blue arrow)
Rotation around N-Cα and Cα-C is not really “free” due to steric blocking, as bulky R-groups of AA side chains effect favourability of the orientation
Free rotation around N-Cα = phi (Φ)
Free rotation around Cα-C = psi (Ψ)
A) psi
B) phi
phi and psi are always between +180° and -180°
clockwise = + ; counter-clockwise = -
Most regions of the Ramachandran plot are inaccessible to proteins because of steric clash
To determine structure we can't only use phi and psi, we also need the omega bond angle
The vast majority of peptide bonds are in the trans configuration
Refers to the orientation of the alpha carbons adjacent to the peptide bond
The peptide bond angle (“ω”)(omega) is 180 ° in this configuration
The energy difference between the cis and trans configuration is not as dramatic in proline
Summary of the interactions that stabilize folded proteins
A) Covalent
B) Disulfide
C) Salt
D) hydrogen
E) electrostatic
F) Van der Waals
G) 1.5
H) 2.2
I) 2.8
J) 3
K) 3.5
The inside the cells is a reducing environment, thus in the
cytoplasm most proteins are reduced so disulfide bonds are rare
Hydrogen bonds:
2 - 6 kJ/mole (if donor/acceptor is charged, and can be stronger in low dielectric field)
Shorter distance between donor and acceptor = STRONGER, however optimal at 3.0 Å.
Longer distance (> 3.0 Å) between donor and acceptor = WEAKER
If donor-H-acceptor well aligned = STRONGER
Electrostatic interactions
-> more negative = more favourable
A) hydrogen
B) Salt
Van der Waals interactions
A) electronic
B) london
Lipid bilayer = many van der Waals interactions add up!
Hydrophobic core of proteins = many van der Waals interactions add up!
A) head
B) acyl
Secondary Structure:
Segments of the main chain in nearly all proteins adopt conformations in which the phi (Φ) and psi (Ψ) torsion angles of the backbone repeat in a regular pattern
Types of Helices:
A) Alpha
B) 3 10
C) Pi
D) Polyproline I
E) Polyproline II
α helix (most prevalent helical form in proteins!)
1.5 Å per residue “rise” along helix axis
3.6 residues per helix “turn” (360˚)
peptide dipoles align, summing to a substantial “helix dipole”
almost exclusively right -handed (because all are L amino acids)
peptide N-H and C=O are similarly aligned along the helix axis leading to a repeating hydrogen bond pattern