3.2.5.5: Variable Oxidation States

Cards (8)

  • Vanadium Chemistry:
    • A - V2+
    • B - V3+
    • C - VO 2+
    • D - VO2 +
    • E - +2
    • F - +3
    • G - +4
    • H - +5
    • Vanadium's oxidation state changes from: 5+ to 4+
    • The colour change that occurs is: yellow to blue
    • Vanadium's oxidation state changes from: 4+ to 3+
    • The colour change that occurs is: blue to green
    • Vanadium's oxidation state changes from: 3+ to 2+
    • The colour change that occurs is: green to violet
  • Redox Potentials
    • Larger ( more +ve) redox potential -> eqm. lies to the right  ∴ species more easily reduced  ∴ better oxidising agent
    • Smaller (more -ve) redox potential -> eqm. lies to left  ∴ species more easily oxidised  ∴ better reducing agent
    • Done in STANDARD CONDITIONS: 298K, 100kPa, [ions] at 1 mol / dm^3
  • Two factors that affect (the size of) redox potentials:
    • pH
    • type of ligand
  • Ligands in Redox Potentials
    • ϵ always calculated in AQUEOUS SOLUTIONS (metal ion surrounded by water molecules)
    • certain ligands other than H2O form stronger bonds with different oxidation states -> redox potential changes from standard value
  • pH in Redox Potentials
    • More acidic solution -> ion more easily reduced (better oxidising agent) -> favours reduction -> eqm. lies to the right
    • More basic/alkaline solution - ion more easily oxidised -> favours oxidation -> eqm. lies to the left
    • Larger, more +ve ϵ value -> eqm. lies to right -> favours reduction of metal
    • Smaller, more -ve value -> eqm. lies to left -> favours oxidation of metal