3.2.5.5: Variable Oxidation States

    Cards (8)

    • Vanadium Chemistry:
      • A - V2+
      • B - V3+
      • C - VO 2+
      • D - VO2 +
      • E - +2
      • F - +3
      • G - +4
      • H - +5
      • Vanadium's oxidation state changes from: 5+ to 4+
      • The colour change that occurs is: yellow to blue
      • Vanadium's oxidation state changes from: 4+ to 3+
      • The colour change that occurs is: blue to green
      • Vanadium's oxidation state changes from: 3+ to 2+
      • The colour change that occurs is: green to violet
    • Redox Potentials
      • Larger ( more +ve) redox potential -> eqm. lies to the right  ∴ species more easily reduced  ∴ better oxidising agent
      • Smaller (more -ve) redox potential -> eqm. lies to left  ∴ species more easily oxidised  ∴ better reducing agent
      • Done in STANDARD CONDITIONS: 298K, 100kPa, [ions] at 1 mol / dm^3
    • Two factors that affect (the size of) redox potentials:
      • pH
      • type of ligand
    • Ligands in Redox Potentials
      • ϵ always calculated in AQUEOUS SOLUTIONS (metal ion surrounded by water molecules)
      • certain ligands other than H2O form stronger bonds with different oxidation states -> redox potential changes from standard value
    • pH in Redox Potentials
      • More acidic solution -> ion more easily reduced (better oxidising agent) -> favours reduction -> eqm. lies to the right
      • More basic/alkaline solution - ion more easily oxidised -> favours oxidation -> eqm. lies to the left
      • Larger, more +ve ϵ value -> eqm. lies to right -> favours reduction of metal
      • Smaller, more -ve value -> eqm. lies to left -> favours oxidation of metal