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Circle 1
Circle 2
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Cards (15)
General form of the equation of a circle
x^2
+
y^2
+
dx
+
ey
+
f
=
0
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Deriving general form from standard form
1.
Expand
(x - h)^2 + (y - k)^2 = r^2
2. Combine and simplify terms
3. Let d =
-2h
, e =
-2k
, f = h^2 + k^2 - r^2
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Deriving standard form from general form
1. Rearrange terms to get
perfect
square
trinomials
2. Complete the square for
x
and
y
terms
3.
Simplify
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Center
of a circle

The
point
(h, k) where h is the
x-coordinate
and k is the y-coordinate
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Radius of a circle
The distance from the
center
to the
circumference
, denoted by r
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The general form of the equation of a circle is
x^2 + y^2 + dx + ey +
f
=
0
View source
To find the center and
radius
from the general form, we need to rearrange the terms to get
perfect
square
trinomials
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Completing
the
square
is a key technique for deriving the
standard form
from the
general
form
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General form of the equation of a circle
x^2 + y^2 + dx + ey + f = 0
View source
Deriving general form from standard form
1. Expand (x - h)^2 + (y - k)^2 = r^2
2. Combine and simplify terms
3. Let d =
-2h
, e =
-2k
, f = h^
2
+
k
^
2 -
r^
2
View source
Deriving standard form from general form
1. Rearrange terms to get
perfect
square
trinomials
2. Complete the
square
for
x
and
y
terms
3. Simplify
View source
Center of a circle
The point (h, k) where
h
is the
x-coordinate
and
k
is the
y-coordinate
View source
Radius of a circle
The distance from the
center
to the
circumference
, denoted by r
View source
The general form of the equation of a circle is
x^2 + y^2 + dx + ey + f = 0
View source
To find the center and radius from the general form, rearrange to get
perfect square trinomials
,
complete
the square, and take the square
root
of the
constant
term
View source