Circle 2

Cards (15)

  • General form of the equation of a circle
    x^2 + y^2 + dx + ey + f = 0
  • Deriving general form from standard form
    1. Expand (x - h)^2 + (y - k)^2 = r^2
    2. Combine and simplify terms
    3. Let d = -2h, e = -2k, f = h^2 + k^2 - r^2
  • Deriving standard form from general form
    1. Rearrange terms to get perfect square trinomials
    2. Complete the square for x and y terms
    3. Simplify
  • Center of a circle

    The point (h, k) where h is the x-coordinate and k is the y-coordinate
  • Radius of a circle
    The distance from the center to the circumference, denoted by r
  • The general form of the equation of a circle is x^2 + y^2 + dx + ey + f = 0
  • To find the center and radius from the general form, we need to rearrange the terms to get perfect square trinomials
  • Completing the square is a key technique for deriving the standard form from the general form
  • General form of the equation of a circle
    x^2 + y^2 + dx + ey + f = 0
  • Deriving general form from standard form
    1. Expand (x - h)^2 + (y - k)^2 = r^2
    2. Combine and simplify terms
    3. Let d = -2h, e = -2k, f = h^2 + k^2 - r^2
  • Deriving standard form from general form
    1. Rearrange terms to get perfect square trinomials
    2. Complete the square for x and y terms
    3. Simplify
  • Center of a circle
    The point (h, k) where h is the x-coordinate and k is the y-coordinate
  • Radius of a circle
    The distance from the center to the circumference, denoted by r
  • The general form of the equation of a circle is x^2 + y^2 + dx + ey + f = 0
  • To find the center and radius from the general form, rearrange to get perfect square trinomials, complete the square, and take the square root of the constant term