Circle 2

    Cards (15)

    • General form of the equation of a circle
      x^2 + y^2 + dx + ey + f = 0
    • Deriving general form from standard form
      1. Expand (x - h)^2 + (y - k)^2 = r^2
      2. Combine and simplify terms
      3. Let d = -2h, e = -2k, f = h^2 + k^2 - r^2
    • Deriving standard form from general form
      1. Rearrange terms to get perfect square trinomials
      2. Complete the square for x and y terms
      3. Simplify
    • Center of a circle

      The point (h, k) where h is the x-coordinate and k is the y-coordinate
    • Radius of a circle
      The distance from the center to the circumference, denoted by r
    • The general form of the equation of a circle is x^2 + y^2 + dx + ey + f = 0
    • To find the center and radius from the general form, we need to rearrange the terms to get perfect square trinomials
    • Completing the square is a key technique for deriving the standard form from the general form
    • General form of the equation of a circle
      x^2 + y^2 + dx + ey + f = 0
    • Deriving general form from standard form
      1. Expand (x - h)^2 + (y - k)^2 = r^2
      2. Combine and simplify terms
      3. Let d = -2h, e = -2k, f = h^2 + k^2 - r^2
    • Deriving standard form from general form
      1. Rearrange terms to get perfect square trinomials
      2. Complete the square for x and y terms
      3. Simplify
    • Center of a circle
      The point (h, k) where h is the x-coordinate and k is the y-coordinate
    • Radius of a circle
      The distance from the center to the circumference, denoted by r
    • The general form of the equation of a circle is x^2 + y^2 + dx + ey + f = 0
    • To find the center and radius from the general form, rearrange to get perfect square trinomials, complete the square, and take the square root of the constant term
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